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dmitriy555 [2]
4 years ago
8

MYTH OR FACT? Eating disorders occur only in fernales. *

Chemistry
1 answer:
sdas [7]4 years ago
3 0

Answer:

myth

Explanation:

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PLZ HELP!!!!!! IN YOUR OWN WORDS PLZ! :D
Neporo4naja [7]

Answer:

String a piece of twine between the cups. Use a long piece of string to help the sound travel farther. Tie a knot in the end of the string to keep it in the cup. Decorate the cups if desired. One person can hold the phone up to their ear and the other person can talk into the other cup. Keep the string tight or the sound waves won’t travel.

Explanation:

4 0
3 years ago
Is neutralizing a base, physical or chemical property?
DIA [1.3K]
Physical property

Have a nice day!
8 0
3 years ago
Read 2 more answers
7. Write a balanced chemical equation for the following reactions and label what type of reaction it is. (3 points)
slamgirl [31]
(A) Naoh + Hno3 == Nano3 + h20.
and it is acid based reaction.
(B) H + Br == Hbr. it is synthesis reaction
and it should be hydrogen gas with bromine gas if that was question then
H2 + Br2 == 2Hbr
(c) 3Agno3 + Alcl3 == Al (No3)3 + 3Agcl
it is double displacement. and we right the polyatomic ion in bracket that’s why no3 is in bracket.
please let me know if you need something
5 0
3 years ago
Read 2 more answers
A body of knowledge must be _____ in order to be considered science.
Law Incorporation [45]
The correct answer is realistic and reliable
5 0
3 years ago
A 47.1 g sample of a metal is heated to 99.0°C and then placed in a calorimeter containing 120.0 g of water (c = 4.18 J/g°C) at
wlad13 [49]

Answer : The metal used was iron (the specific heat capacity is 0.44J/g^oC).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

C_1 = specific heat of metal = ?

C_1 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 47.1 g

m_2 = mass of water = 120 g

T_f = final temperature of water = 24.5^oC

T_1 = initial temperature of metal = 99^oC

T_2 = initial temperature of water = 21.4^oC

Now put all the given values in the above formula, we get

47.1g\times c_1\times (24.5-99)^oC=-120g\times 4.18J/g^oC\times (24.5-21.4)^oC

c_1=0.44J/g^oC

Form the value of specific heat of metal, we conclude that the metal used in this was iron.

Therefore, the metal used was iron (the specific heat capacity is 0.44J/g^oC).

3 0
3 years ago
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