3Ca(NO3)2(aq) +Fe2(SO4)3(aq)-----> 3CaSO4(s)+ 2Fe(NO3)3(aq)
3Ca²⁺ + 6 NO3 ⁻ +2 Fe ³⁺ +3SO4²⁻ -----> 3CaSO4(s)+2 Fe ³⁺+ 6 NO3 ⁻
3Ca²⁺+3SO4²⁻---->3CaSO4(s)
Ca²⁺+SO4²⁻---->CaSO4(s)
Answer:
Molecular formula is C₂₆H₃₆O₄
Explanation:
The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.
In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H
In 412 g of compound we would have:
(412 . 75.69) / 100 = 311.8 of C
(412 . 15.51) / 100 = 63.9 g of O
(412 . 8.80) / 100 = 36.2 g of H
Now, we can determine the moles of each, that are contained in 1 mol of compound.
312 g / 12 g/mol 26 C
64 g / 16 g/mol = 4 O
36 g / 1 g/mol = 36 H
Molecular formula is C₂₆H₃₆O₄
Answer:
2.33 *10^1 g
Explanation:
.595 mol *39.0983 g/1 mol = 23.2634 > 2.33 *10^1 g
Answer:
2C2H2 + 5O2 → 4CO2 + 2H2O
Explanation:
Uranium, which is number 92
