Answer:
Explanation:
Given
car A had a head start of
and it starts at x=0 and t=0
Car B has to travel a distance of
where is the distance travel by car A in time t
distance travel by car A is
For car B with speed
If the partial pressures of the three gases in the tank are 38.39 atm of O2, 3.38 atm of He, and 25.33 atm of N2, what is the to
1 answer:
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Since momentum is a vector quantity, take any direction as positive and other as negative. Answer won't change.
Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity = 60 mph = 26.8224 m/s
Final velocity = 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk = m(
² -
² )
we substitute
Δk = ×1814.37( (26.8224)² - (13.4112)² )
Δk = × 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Answer:
Explanation:
The heaviside function is defined as:
so we see that the Heaviside function "switches on" when, and remains switched on when
If we want our heaviside function to switch on when , we need the argument to the heaviside function to be 0 when
Thus we define a function f:
The term inside the heaviside function makes sure to displace the function 5 units to the right.
Now we just need to add a scale up factor of 240 V, because thats the voltage applied after the heaviside function switches on. ( when
, so it becomes just a 1, which we can safely ignore.)
Therefore our final result is:
I have made a sketch for you, and added it as attachment.
