Answer:
Explanation:
Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.
The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:
Substitute the values into the formula.
Multiply.
- 1 kilogram meter per square second is equal to 1 Newton.
- Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.
The force required is <u>252.5 Newtons</u>.
The question is incomplete! The complete question along with answer and explanation is provided below.
Question:
A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters.
What is the change in the potential energy (in Joules) of the mass as it goes up the incline?
If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the incline, how much work is done by that force?
Given Information:
Mass = m = 0.5 kg
Horizontal distance = d = 40 cm = 0.4 m
Vertical distance = h = 7 cm = 0.07 m
Normal force = Fn = 1 N
Required Information:
Potential energy = PE = ?
Work done = W = ?
Answer:
Potential energy = 0.343 Joules
Work done = 0.39 N.m
Explanation:
The potential energy is given by
PE = mgh
where m is the mass of the object, h is the vertical distance and g is the gravitational acceleration.
PE = 0.5*9.8*0.07
PE = 0.343 Joules
As you can see in the attached image
sinθ = opposite/hypotenuse
sinθ = 0.07/0.4
θ = sin⁻¹(0.07/0.4)
θ = 10.078°
The horizontal component of the normal force is given by
Fx = Fncos(θ)
Fx = 1*cos(10.078)
Fx = 0.984 N
Work done is given by
W = Fxd
where d is the horizontal distance
W = 0.984*0.4
W = 0.39 N.m
Answer:
1 x 10¹²J
Explanation:
Given parameters:
Mass of the water pumped = 2.05 x 10⁸kg
Height = 500m
Unknown:
Potential energy = ?
Solution:
The potential energy amassed by water at this height is expressed as;
P.E = mgH
m is the mass
g is the acceleration due to gravity
H is the height
Insert the parameters and solve;
P.E = 2.05 x 10⁸ x 9.8 x 500 = 1 x 10¹²J
Answer:
t = 2.97[s]
Explanation:
To solve this problem we must use the following kinematics equations, we must bear in mind that the positive sign of the acceleration value means that the car is increased its speed.
where:
x - xo = 180 [ft]
a = acceleration [ft/s^2]
Vo = initial velocity = 53 [ft/s]
Vf = final velocity = 68 [ft/s]
Now replacing we find:
(68^2) = (53^2) + (2*a*180)
a = 5.04 [ft/s^2]
Now using the following equation:
68 = 53 + (5.04*t)
t = (68 - 53)/5.04
t = 2.97[s]
2*3.5 = 7m/s
You multiply the acceleration per the time (they both are in seconds, otherwise, you should set them in the same units).