Answer:
The pressure exerted by the gas is 100kPa
Explanation:
Let's apply the Charles Gay Lussac law, to solve the question.
At constant volume the pressure varies proportionally with the temperature.
P initial / T° initial = P final / T° final
50kPa / 20°C = P final / 40°C
Temperature has increased the double, so the pressure will be increased, the double too.
100 kPa
Answer: 1. b
2. c
3. a
Explanation: A chemical reaction in equilibrium is actually in a dynamic euqilibrium, which means that changing a condition will make the equilibrium move to counteract the action and reestate the equilibrium.
For example, in the reaction:
N2(g) + 3H2(g) ⇄ 2NH3(g)
1. <u>Adding H2</u>: if you add the reagent, to reestate the equilibrium, the reaction will produce more products so, it will <u>move to the right</u>;
2. A <u>catalyst</u> doesn't interfere in the equilibrium, because it moves to the right and to the left at the same extent. Therefore, there is <u>no effect</u>.
3. <u>Decrease the pressure</u>: when you decrease the pressure of a reaction, the equilibrium will make the pressure increase again by moving towards the side of the reaction which has more molecules, so, it <u>shifts to the left</u>;
Answer:
1) a. 2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).
2) a. 0.4477 mol.
b. 0.4477 mol.
c. 72.61 g.
Explanation:
1) Consider the following reaction: iron (s) + chlorine (g) à iron (III) chloride
<em>a. Write the balanced chemical equation.</em>
- The balanced equation should apply the law of conversation of mass that the no. of different atoms is equal in both sides of the reaction (reactants and products sides).
So, the balanced chemical equation is:
<em>2Fe(s) + 3Cl₂(g) → 2FeCl₃(s).</em>
It is clear that 2 mol of Fe(s) react with 3 mol of Cl₂(g) to produce 2 mol of FeCl₃(s).
<em>2) 25.0 g of iron reacts with excess chlorine gas. </em>
<em>a. Calculate the moles of iron reactant.</em>
- The no. of moles of Fe (n) can be calculated using the relation:
<em>n = mass/molar mass =</em> (25.0 g)/(55.845 g/mol) = <em>0.4477 mol.</em>
<em>b. Calculate the moles of iron (III) chloride.</em>
<em><u>Using cross multiplication:</u></em>
2 mol of Fe produce → 2 mol of FeCl₃, from stichiometry.
∴ 0.4477 mol of Fe produce → 0.4477 mol of FeCl₃.
∴ The no. of moles of iron (III) chloride produced is 0.4477 mol.
<em>c. Calculate the mass of iron (III) chloride.</em>
- We can calculate the mass of iron (III) chloride produced using the relation:
mass of iron (III) chloride = (no. of moles)*(molar mass) = (0.4477 mol)*(162.2 g/mol) = 72.61 g.
Water will heat up Th e fastest
The electron domain geometry is trigonal bipyramidal while the molecular geometry of the compound is seesaw.
The shapes of molecules is determined by the number of electron pairs on the valence shell of the central atom in the molecule. These electron domains include lone pairs and bond pairs.
The lone pairs only contribute towards the electron domain geometry and not the molecular geometry. SCl4 has five electron domains hence its electron domain geometry is trigonal bipyramidal. The molecular geometry of the compound is seesaw.
Learn more: brainly.com/question/6505878
