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DanielleElmas [232]
4 years ago
10

Write the formula for a compound of manganese (IV) hydroxide.?

Chemistry
1 answer:
Oxana [17]4 years ago
5 0
You first add the manganese and exchange the number of electrons needed with the hydroxide. While the hydroxide needs only 1 electron the manganese needs 4, so after you exchange the electrons the manganese will be just 1 atom while the hydroxide is 4. Mn(OH)4
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Answer:

Explanation:

1) Find number of each of the type of atom that is present in the compound, using the chemical formula .

2) Then multiply number of atoms of each element that is present in the compound with the atomic weight of each of the element

3) Add everything together and add the units (grams/mole ) after the number

Let finds that of water

Chemical formula of water is (H20 )

hydogens atoms= 2

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Total number of atoms of Hydrogen from the formula (H2O)= 2

Total number of atoms of Oxygen from the formula (H2O)= 1

the molar mass=

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Add together= (16+2)

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Then add the unit, we have(18 g/mol.)

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