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4 years ago

Write the formula for a compound of manganese (IV) hydroxide.?

1 answer:

5 0

You first add the manganese and exchange the number of electrons needed with the hydroxide. While the hydroxide needs only 1 electron the manganese needs 4, so after you exchange the electrons the manganese will be just 1 atom while the hydroxide is 4. Mn(OH)4

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How do atoms and elements differ from each other?

strojnjashka [21]

Answer:

A particular atom will have the same number of protons and electrons and most atoms have at least as many neutrons as protons. An element is a substance that is made entirely from one type of atom. For example, the element hydrogen is made from atoms containing just one proton and one electron.

Explanation:

8 0

3 years ago

Read 2 more answers

If 5.0 grams of sucrose, C12H22O11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting soluti

GaryK [48]

Answer : The boiling point of the resulting solution is, $100.6^oC$

Explanation :

Formula used for Elevation in boiling point :

$\Delta T_b=i\times k_b\times m$

or,

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^oC$

$k_b$ = boiling point constant = $0.52^oC/m$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute (sucrose) = 5.0 g

$w_1$ = mass of solvent (water) = 10.0 g

$M_2$ = molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}$

$T_b=100.6^oC$

Therefore, the boiling point of the resulting solution is, $100.6^oC$

5 0

3 years ago

Determine the electron geometry, molecular geometry, and idealized bond angles for each of the following molecules. CF4CF4 NF3NF

vfiekz [6]

Answer:

CF4

Molecular geometry- tetrahedral

Electron geometry- tetrahedral

NF3

-molecular geometry - trigonal pyramidal

Electron geometry - tetrahedral

OF2

Molecular geometry - bent

Molecular geometry - tetrahedral

H2S

Molecular geometry- bent

Electron geometry - tetrahedral

Explanation:

According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electron pairs on the valence shell of the central atom in the molecule.

For all the compounds listed, the central atom has four points of electron density. This correspond to a tetrahedra electron pair geometry. The presence of lone pairs on the central atom of OF2,NF3 and H2S accounts for the departure of the observed molecular geometry from the geometry and idealized bond angle predicted on the basis of the VSEPR theory.

5 0

3 years ago

A student observed that a small amount of acetone sprayed on the back of the hand felt very cool compared to a similar amount of

Alla [95]

Answer:

D.) The higher vapor pressure of acetone results in more rapid evaporation and heat loss

Explanation:

Acetone being liquid with very low boiling point and hence can be easily be converted to gaseous state .

And ,

Therefore have higher vapour pressure and as liquid gets converted to gas , the process of evaporation takes place and leads to loss of heat .

Hence , from the given options , the most appropriate option according to given statement of the question is ( d ) .

4 0

4 years ago

Suggest why sodium and hydrogen ions do not diffuse at the same rate

Troyanec [42]

Answer:

sodium has got ionic bonds that are weak

compared to hydrogen covalent bonds that are strong

8 0

3 years ago