3 years ago

5. What happens to the arrangement of water molecules as ice melts?

Physics

1 answer:

m_a_m_a [10]3 years ago

7 0

Answer: I am pretty sure the answer is B

Explanation: If not sorry bro.

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A ball swings in a horizontal circle. If the radius and the frequency are both doubled, by what factor does the tension in the s

kherson [118]

Answer:

The tension increases by a factor of 8

Explanation:

We know that the tension, T in the string equals the centripetal force on the ball. So

T = mrω² = mr(2πf)² = 4mrπ²f² where m = mass of ball, r = radius of circle and f = frequency of rotation

If the radius and frequency are doubled, then r = 2r and f = 2f. So, the new tension is T' = 4mr'π²f'² = 4m(2r)π²(2f)² = 4 × 2 × 4mrπ²f² = 8T

Since T' = 8T,

So T'/T = 8.

So the tension increases by a factor of 8

4 0

3 years ago

Which matter exists in the gaseous state at room temperature?

gulaghasi [49]

I would say (c.oxygen)

6 0

3 years ago

4.A 13.6 kg bag of dog food is held 1.25 m above the ground. Calculate the

Tanzania [10]

Answer:

PE = mgh = 13.6(9.81)(1.25) = 166.77 ≈ 167 J

Explanation:

5 0

3 years ago

Yurem is pulling a wagon across the playground with a force of 10 N. He asks Elianna to help. She agrees and pushes the back of

salantis [7]

Answer:

22 N applied force

Explanation: Since they are both pushing the wagon in the same direction the force adds up.

7 0

3 years ago

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A golfer hits a shot to a green that is elevated 3.20 m above the point where the ball is struck. The ball leaves the club at a

dem82 [27]

Answer:

16.17 m/s

Explanation:

h = 3.2 m

u = 18.1 m/s

Angle of projection, θ = 49°

Let H be the maximum height reached by the ball.

The formula for the maximum height is given by

$H=\frac{u^{2}Sin^{2}\theta }{2g}$

$H=\frac{18.1^{2}\times Sin^{2}49 }{2\times 9.8}=9.52 m$

The vertical distance fall down by the ball, h' H - h = 9.52 - 3.2 = 6.32 m

Let v be the velocity of ball with which it strikes the ground.

Use third equation of motion for vertical direction

$v_{y}^{2}=u_{y}^{2}+2gh'$

here, uy = 0

So,

$v_{y}^{2}=2\times 9.8 \times 6.32$

vy = 11.13 m/s

vx = u Cos 49 = 18.1 x 0.656 = 11.87 m/s

The resultant velocity is given by

$v=\sqrt{v_{x}^{2}+v_{y}^{2}}$

$v=\sqrt{11.87^{2}+11.13^{2}}$

v = 16.27 m/s

7 0

4 years ago