Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed

Where. d = distance
t = time
Put the value into the formula

during that run
(b). We need to calculate their velocity
Using formula of speed

Put the value into the formula


Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position

Put the value into the formula


Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.