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Delvig [45]
3 years ago
13

A sample of radium-226 decays to form radon-222. A solution of AgNO3 and NaCl reacts to form AgCl and NaNO3. How would an increa

se in the amounts of reactants affect these reaction rates?
Chemistry
2 answers:
VLD [36.1K]3 years ago
3 0
<span>The rate of the chemical reaction increases, but the rate of the nuclear decay stays the same.</span>
Nuetrik [128]3 years ago
3 0

Answer: An increase in the amount of radium-226 will increase the reaction rate as radioactive decay follows first order kinetics.

An increase in the amount of  AgNO_3 and NaCl will increase the reaction rate as the reaction follows first order kinetics with respect to AgNO_3 and first order with respect to NaCl.

^{226}_{88}\textrm{Ra}\rightarrow^{222}_{86}\textrm{Rn} +^4_2\textrm{He}

rate= k[Ra]^1

If the amount of radium is doubled , the rate of the reaction also doubles.

AgNO_3 + NaCl\rightarrow AgCl +NaNO_3

rate= k[AgNO_3]^1[NaCl]^1

If only the amount of AgNO_3 is doubled , the rate of the reaction also doubles. If only the amount of NaCl is doubled , the rate of the reaction doubles. lf the concentration of  AgNO_3 and NaCl both are doubled, the reaction rate becomes 4 times.




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etermine the molar concentration of magnesium ions in a solution formed by mixing 100.0 mL of 0.100 M MgCl, solution with 100.0
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Molar concentration of magnesium ions in the final solution is 0.2 M.

Explanation:

c=\frac{n}{V}

c = Concentration of the solution

n =   moles of the compound

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Moles of MgCl_2 in 100 mL solution= n

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2) Molarity of Mg_3(PO_4)_2 solution = 0.100 M

Volume of Mg_3(PO_4)_2 solution = 100.0 mL = 0.1 L

Moles of Mg_3(PO_4)_2 in 100 mL solution= n'

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Total volume after mixing = 0.1 L + 0.1 L = 0.2 L

Molar concentration of magnesium ions in the final solution:[Mg^{2+}]

[Mg^{2+}]=\frac{0.04 mol}{0.2 L}=0.2 mol/L

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