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Delvig [45]
3 years ago
13

A sample of radium-226 decays to form radon-222. A solution of AgNO3 and NaCl reacts to form AgCl and NaNO3. How would an increa

se in the amounts of reactants affect these reaction rates?
Chemistry
2 answers:
VLD [36.1K]3 years ago
3 0
<span>The rate of the chemical reaction increases, but the rate of the nuclear decay stays the same.</span>
Nuetrik [128]3 years ago
3 0

Answer: An increase in the amount of radium-226 will increase the reaction rate as radioactive decay follows first order kinetics.

An increase in the amount of  AgNO_3 and NaCl will increase the reaction rate as the reaction follows first order kinetics with respect to AgNO_3 and first order with respect to NaCl.

^{226}_{88}\textrm{Ra}\rightarrow^{222}_{86}\textrm{Rn} +^4_2\textrm{He}

rate= k[Ra]^1

If the amount of radium is doubled , the rate of the reaction also doubles.

AgNO_3 + NaCl\rightarrow AgCl +NaNO_3

rate= k[AgNO_3]^1[NaCl]^1

If only the amount of AgNO_3 is doubled , the rate of the reaction also doubles. If only the amount of NaCl is doubled , the rate of the reaction doubles. lf the concentration of  AgNO_3 and NaCl both are doubled, the reaction rate becomes 4 times.




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Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch
matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.


Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

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On adding HCl (strong acid) in water, it will completely dissociates into ions (H^{+} and Cl^{-}) and thus, it is a strong electrolyte.

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On adding NaOH (strong base) in water, it will completely dissociates into ions (Na^{+} and  OH^{-}) and thus, it is a strong electrolyte.

  • Formic acid, HCOOH

On adding HCOOH (weak acid) in water, it will partially dissociates into ions (H^{+} and  HCOO^{-}) and thus, it is a weak electrolyte.

  • Methyl amine, CH_3NH_2

On adding CH_3NH_2 (weak base) in water, it will partially dissociates into ions (CH_3NH_3^{+} and  OH^{-}) and thus, it is a weak electrolyte.

  • Potassium chloride, KCl

On adding KCl in water, it will completely dissociates into ions (K^{+} and  Cl^{-}) and thus, it is a strong electrolyte.

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On adding C_2H_5OH in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

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3 0
3 years ago
Which element has the same number of energy levels as aluminum (Al) and the same number of valence electrons as calcium (Ca)
GREYUIT [131]

Answer:

magnesium (Mg)

Explanation:

8 0
3 years ago
Read 2 more answers
2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to
evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

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