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s2008m [1.1K]
3 years ago
14

Explain why a wooden spoon a better choice then a metal spoon for stirring a boiling pot I soup

Physics
1 answer:
VladimirAG [237]3 years ago
5 0
Metal is a conductor of heat while wood does the opposite so having a wooden spoon would keep you from burning your hand
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A. praised
krok68 [10]

Answer:

14. scolded

15. supporter

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17. comfortable

18. outdated

19. drink

20. it can be fantastic or wealthy

8 0
2 years ago
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Which will most likely be a consequence as fossil fuel reserves are depleted?
bazaltina [42]
It honestly depends. Fossil fuels are non-renewable so if reserves are depleting there is a threat of them running out and/or more pollution.
8 0
2 years ago
you have a 200 kg bag being lifted with a block and tackle. If you pull with 100 newtons what is the MA of the system?
Korvikt [17]

Answer:

The mechanical advantage of the system is equal to 19.62

Explanation:

The ratio of the force produced by a machine to the force applied to it is called mechanical advantage. In other words it is the ratio of output force to the input force.

In this problem mass=200kg

applied force=100N  

input force=100N

output force=mg=200 \times 9.8=196N.

mechanical advantage MA= \frac{1960}{100}=19.6

It gives an idea about the efficiency of a mechanical device. It is indeed a measure of force amplification. In block and tackle system an assembly of ropes and pulleys is used to lift loads. When the moving block is supported by a  greater  number of rope sections the force amplification will be more.

7 0
3 years ago
Read 2 more answers
A car’s engine provides a forward force of 500 N. It is opposed by a resistive force of 200 N. The car accelerates forwards for
wariber [46]

Answer:

Explanation:

W = Fd

Engine 500(20) = 10000 J

friction 200(-20) = -4000 J

Energy increase is 10000 - 4000 = 6000 J

5 0
3 years ago
A block of mass m = 2.0 kg lies on a rough ramp that is inclined at an angle θ = 20oto the horizontal. A force F of magnitude 5.
Marina86 [1]

Answer:

a) 0.64 b) 2.17m/s^2 c) 8.668joules

Explanation:

The block was on the ramp, the ramp was inclined at 20degree. A force of 5N was acting horizontal to the but not parallel to the ramp,

Frictional force = horizontal component of the weight of the block along the ramp + the applied force since the block was just about move

Frictional force = mgsin20o + 5N = 6.71+5N = 11.71

The force of normal = the vertical component of the weight of the block =mgcos20o = 18.44

Coefficient of static friction = 11.71/18.44= 0.64

Remember that g = acceleration due to gravity (9.81m/s^2) and m = mass (2kg)

b) coefficient of kinetic friction = frictional force/ normal force

Fr = 0.4* mgcos 20o = 7.375N

F due to motion = ma = total force - frictional force

Ma = 11.71 - 7.375 = 4.335

a= 4.335/2(mass of the block) = 2.17m/s^2

C) work done = net force *distance = 4.335*2= 8.67Joules

8 0
3 years ago
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