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Rus_ich [418]
3 years ago
8

A 25.0 mL sample of 0.123 M HCl was titrated with 18.04 mL of NaOH . What is the concentration of the NaOH ?

Chemistry
1 answer:
Blababa [14]3 years ago
5 0

Answer:

0.170 M

Explanation:

M1V1=M2V2

(25.0mL)(0.123M)=(18.04mL)(x)

x= 0.170 M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc. :)

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2 years ago
A 0.271g sample of an unknown vapor occupies 294ml at 140C and 874mmHg. The emperical formula of the compound is CH2. How many m
Phoenix [80]
Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
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moles = mass / Mr
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Formula of substance:
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7 0
3 years ago
Please help fast, I will give brainliest!
miss Akunina [59]
I think it’s 20 mol
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4 0
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