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Rus_ich [418]
3 years ago
8

A 25.0 mL sample of 0.123 M HCl was titrated with 18.04 mL of NaOH . What is the concentration of the NaOH ?

Chemistry
1 answer:
Blababa [14]3 years ago
5 0

Answer:

0.170 M

Explanation:

M1V1=M2V2

(25.0mL)(0.123M)=(18.04mL)(x)

x= 0.170 M

* Please text me at 561-400-5105 for tutoring: I can do assignments, labs, exams, etc. :)

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