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3 years ago

Can you create the needed environment on earth to stop an atom completely

Chemistry

1 answer:

Tresset [83]3 years ago

4 0

<span>Practically, the work needed to remove heat from a gas increases the colder.</span>

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Why is hydgron content with only 2 electrons instead of 8 like atoms in periods greater than 1?

Cerrena [4.2K]

Because the sublevels 1s only has one shape ,and it only contains 2 elections...

5 0

3 years ago

Give the number of protons, neutrons and electrons in 99Tc

miss Akunina [59]

Explanation:

Tc - 99 is technetium 99.

It is a radioactive element that decays spontaneously. It has a half-life of 211,000 years and decays to stable ruthenium.

On the periodic table, it has an atomic number of 43;

Mass number = 99

Atomic number = number of protons = number of electrons in atom

Number of protons in Tc is 43

electron is 43

Mass number = number of protons + number of neutrons

Number of neutrons = mass number - number of protons = 99-43 = 56

learn more:

Atomic number brainly.com/question/2057656

#learnwithBrainly

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3 years ago

When a solid has energy added and turns to a liquid what is it called?

Phoenix [80]

Melting (solid to liquid)

4 0

3 years ago

chlorine has 7 outer energy level electrons and argon has 8. what is the difference in the reactivity of these two elements?

Lunna [17]

Chlorine is more reactive than argon, because argon is not reactive at all. Chlorine only has to gain 1 valence electron

6 0

3 years ago

Read 2 more answers

The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

3 0

3 years ago