Answer:
The current in primary coil is 2.08 A.
Explanation:
Given that,
Power = 500 W
Voltage = 16 kV
Number of turns = 80000
We need to calculate the number of current
Using formula of voltage
Put the value into the formula
We need to calculate the current in secondary coil
Using formula of current
We need to calculate the current in primary coil
Put the value into the formula
Hence, The current in primary coil is 2.08 A.
Answer:
Density of iron is higher than the density of oxygen because iron is solid and the particles in it are very compact but oxygen is not dense as it is gas and particles in it are loosely packed.
The average rate at which energy is transmitted along the string is 15.1 J/s.
<h3>
What is average power of a wave?</h3>
The average power of a sinusoidal wave is proportional to the square of the amplitude of the wave and the square of the angular frequency of the wave
P = ¹/₂μω²A²v
where;
- ω is angular frequency = 10π rad/s
- A is amplitude of the wave, = 0.35
- μ is linear mass density = 75 g/m = 0.075 kg/m
- k is angular wave number, k = 3π /m
- v is speed of the wave = ?
v = ω/k
v = (10π) / (3π)
v = 3.33 m/s
P = ¹/₂μω²A²v
P = ¹/₂(0.075)(10π)²(0.35)²(3.33)
P = 15.1 J/s
Thus, the average rate at which energy is transmitted along the string is 15.1 J/s.
Learn more about average power of a wave here: brainly.com/question/24228412
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Answer:
35 N
Explanation:
F = ma
centripetal force = 10(3.5) = 35 N