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siniylev [52]
3 years ago
10

A two-slit pattern is viewed on a screen 1.26 m from the slits. If the two fourth-order maxima are 53.6 cm apart, what is the to

tal width of the central bright fringe?
Physics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

= 6.55cm

Explanation:

Given that,

distance = 1.26 m

distance between  two fourth-order maxima = 53.6 cm

distance between central bright fringe and fourth order maxima

y = Y / 2

  =  53.6cm / 2

  = 26.8 cm

  =0.268 m

tan θ = y / d

         = 0.268 m /  1.26 m

         = 0.2127

       θ = 12°

4th maxima

d sinθ = 4λ

d / λ = 4 / sinθ

d / λ = 4 / sin 12°

d / λ = 19.239

for first (minimum)

d sinθ = λ / 2

sinθ =  λ / 2d

       =  1 / 2(19.239)

       = 1 / 38.478

       = 0.02599

    θ =  1.489°

tan θ = y / d

y = d tan θ

  = 1.26 tan 1.489°

  = 0.03275

the total width of the central bright fringe  

Y = 2y

  = 2(0.03275)

  = 0.0655m

  = 6.55cm

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Examples of rectilinear motion<br>​
EleoNora [17]

Answer:

Examples for Rectilinear Motion

1) The use of elevators in public places is an example of rectilinear motion.

2) Gravitational forces acting on objects resulting in free fall is an example of rectilinear motion.

3) Kids sliding down from a slide is a rectilinear motion.

4) The motion of planes in the sky is a rectilinear motion.

7 0
3 years ago
Read 2 more answers
A bouncy ball is being thrown upwards with a velocity of 34 meters per second if you caught the ball at the same height you rele
Serga [27]

It took the ball 6.94 seconds to make the trip

Explanation:

A bouncy ball is being thrown upwards with a velocity of 34 meters per

second and you caught the ball at the same height you released it

1. The initial velocity of the ball is 34 m/s upward

2. The acceleration of gravity is -9.8 m/s²

3. You caught the ball at the same height you released it

We need to find how long it takes the ball to make the trip

You caught the ball at the same height you released it, then

→ The displacement of the trip s =  zero meter

→ The ball thrown upward with initial velocity u = 34 m/s

→ The acceleration of gravity g = -9.8 m/s²

→ s = u t + \frac{1}{2} g t²

Substitute the values of u , g , s in the rules

→ 0 = 34 t + \frac{1}{2} (-9.8) t²

→ 0 = 34 t - 4.9 t²

Multiply both sides by -1

→ 4.9 t² - 34 t = 0

Take t as common factor

→ t(4.9 t - 34) = 0

Equate each factor by 0

→ t = 0 ⇒ initial position

→ 4.9 t - 34 = 0

Add 34 to both sides

→ 4.9 t = 34

Divide both sides by 4.9

→ t = 6.94 seconds ⇒ final position

It took the ball 6.94 seconds to make the trip

Learn more:

You can learn more about free fall in brainly.com/question/5531630

#LearnwithBrainly

5 0
3 years ago
What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a
Montano1993 [528]

Answer:

   f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

speed of sound = 331 m/s

By Doppler's effect

f' = (\dfrac{v}{v-v_s}})f

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

f' = \dfrac{341}{341-24.7}}\times 3400

   f' = 1.078 x 3400

   f' = 3665.51 Hz

The frequency received by the stationary mouse is equal to 3665.51 Hz

6 0
3 years ago
(33%) Problem 3: Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1100 kg and i
expeople1 [14]

Answer:

The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

Explanation:

Given that,

Mass of first car = 1100 kg

Velocity of first car = 8.5 m/s

Mass of second car = 650 kg

Velocity of second car = 17.5 m/s

Suppose we need to find the final velocity of the cars and direction of the cars.

We need to calculate the velocity of the car in west direction

Using conservation of momentum in west direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{x}

v_{x}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{x}=\dfrac{1100\times0+650\times17.5}{1100+650}

v_{x}=6.5\ m/s

We need to calculate the velocity of the car in south direction

Using conservation of momentum in south direction

m_{f}v_{f}+m_{s}v_{s}= (m_{f}+m_{s})v_{y}

v_{y}=\dfrac{m_{f}v_{f}+m_{s}v_{s}}{(m_{f}+m_{s})}

Put the value into the formula

v_{y}=\dfrac{1100\times8.5+650\times0}{1100+650}

v_{y}=5.3\ m/s

We need to calculate the final velocity of the cars

Using formula of velocity

v_{eq}=\sqrt{(6.5)^2+(5.3)^2}

v_{eq}=8.38\ m/s

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

Put the value into the formula

\tan\theta=\dfrac{5.3}{6.5}

\theta=\tan^{-1}(\dfrac{5.3}{6.5})

\theta=39.1^{\circ}

Hence, The final velocity of the cars is 8.38 m/s at an angle 39.1° south of west.

8 0
3 years ago
Help please! Will give brainly! and thanks.
kipiarov [429]
<h2>Answer:</h2>

All the energy sources are correctly matched with their category.

Explanation:

Renewable energy sources:

These are energy sources which can be replenished as they don't in involves the irreversible phase change.

These resources can never be ended as they can be used again and again.

Wind, geothermal, biomass, bio gas are example of renewable energy sources.

Non renewable energy sources:

These are the energy source which can never be replenished after one time use. They undergo the chemical irreversible change.

These sources are lacking with the passage of time because they can never be reused.

Oil, gas, coal and natural gas are examples.

7 0
4 years ago
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