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siniylev [52]
3 years ago
10

A two-slit pattern is viewed on a screen 1.26 m from the slits. If the two fourth-order maxima are 53.6 cm apart, what is the to

tal width of the central bright fringe?
Physics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

= 6.55cm

Explanation:

Given that,

distance = 1.26 m

distance between  two fourth-order maxima = 53.6 cm

distance between central bright fringe and fourth order maxima

y = Y / 2

  =  53.6cm / 2

  = 26.8 cm

  =0.268 m

tan θ = y / d

         = 0.268 m /  1.26 m

         = 0.2127

       θ = 12°

4th maxima

d sinθ = 4λ

d / λ = 4 / sinθ

d / λ = 4 / sin 12°

d / λ = 19.239

for first (minimum)

d sinθ = λ / 2

sinθ =  λ / 2d

       =  1 / 2(19.239)

       = 1 / 38.478

       = 0.02599

    θ =  1.489°

tan θ = y / d

y = d tan θ

  = 1.26 tan 1.489°

  = 0.03275

the total width of the central bright fringe  

Y = 2y

  = 2(0.03275)

  = 0.0655m

  = 6.55cm

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Answer:

The correct option is;

d) All of the above

Explanation:

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Therefore, all of the above are correct.

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3 years ago
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Answer:

Momentum of bullet

P = 2.72 kg m/s

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Explanation:

As we know that momentum is defined as the product of mass and velocity

here we know that

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velocity of bullet = 340 m/s

momentum of the bullet is given as

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P = 2.72 kg m/s

Now we have

mass of baseball = 0.2 kg

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A wheelchair moves upward on a 7.1 degree ramp at a speed of 20km/h what is the horizontal velocity
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2 years ago
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It will take 313.376 sec to raise temperature to boiling point

Explanation:

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Current i = 4.50 A

So resistance R=\frac{V}{i}=\frac{120}{4.50}=26.666ohm

Heat flow in resistor will be equal to Q=i^2Rt

It is given that this heat is used for boiling the water

Mass of the water = 0.525 kg = 525 gram

Specific heat of water 4.186 J/gram/°C

Initial temperature is given as 23°C

Boiling temperature of water = 100°C

So change in temperature = 100-23 = 77°C

Heat required to raise the temperature of water Q=mc\Lambda T

So 4.50^2\times 26.666\times t=525\times 4.186\times 77

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5 0
3 years ago
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Answer:

t=2s

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And putting all together:

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Since we want the time taken:

t=\frac{mv_f^2}{2P}

Which for our values is:

t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s

7 0
3 years ago
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