Question

A mechanics shop has a 16,500 N car sitting on a large car lift of 125 cm^2 piston. How much force is needed to be applied to the small piston of area 4.51 cm^2 to lift it?

Answer 1

Answer:595.32 N

Explanation:

Given

Mechanic shop has a car of weight($F_1$) 16,500 N

Area of lift($A_1$)=$125 cm^2$

Area of small piston($A_2$)=$4.51 cm^2$

According to pascal's law pressure transmit will be same in all direction in a closed container

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$F_2=F_1\frac{A_2}{A_1}$

$F_2=16,500\times \frac{4.51}{125}=595.32 N$