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s2008m [1.1K]
4 years ago
10

Material from an environmental study was suspected to contain the banned pesticide, Aldrin, of which you have a pure sample. Gas

chromatography showed 6 peaks. How would you determine unequivocally which of these peaks represented Aldrin?
Chemistry
1 answer:
Anna35 [415]4 years ago
7 0

Answer:

In order  to determine unequivocally which of the peaks represent Aldrin, I would run the pure sample through the chromatography equipment.

Explanation:

Gas chromatography is a technique that separates molecules based on their volatility and interaction with both the stationary phase.

The peaks on the chromatogram show how long a substance took to leave the column. Since each different substance substance will leave the column at a different time, each peak can be attributed to a substance.

Therefore, to know which of the 6 peaks represent Aldrin, it is necessary to run the pure Aldrin in the chromatography equipment and see the time of the peak. Then you just need to compare both chromatograms and indentify Aldrin.

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If a patient requires 30g/day of some medication and it comes in 500 mg tablets , how many tablets does this patient need in one
Anna11 [10]
Since 1000 mg=1g 
            500mg=?
500/1000*1g=0.5g
       Since we know that 500mg is 0.5g then divide 30g by 0.5g
30/0.5=60
Therefore the patients needs to take 60 tablets a day.
4 0
4 years ago
Which of the following aqueous solutions will have the lowest freezing point? a. 0.75 m (NH4)3PO4 b. 1.0 m CaSO4 c. 1.0 m LiCl d
Nataly [62]

Answer: a. 0.75m (NH4)3PO4 will have the lowest freezing point .

Explanation: Freezing point decreases as the concentration of the solute substance increases. Assuming the same solvent for all of them, for instance water.

∆T= i.Kf.b

∆T= freezing point depression

i= vant Hoff factor

Kf= molality

Assuming water to be the solvent for all Kf=1.86°C/M

VANT HOFF FACTORS :

For (NH4)3PO4

This has 3 ionic bonding and 1 covalent bonding making it 4 bond

Therefore i=4

For CaSO4

This has 1 metallic bond and 1 covalent bond making it 2 bond.

Therefore i=2

For LiCl

This has 1 metallic bond and 1 non metallic bond making it 2 bond.

Therefore i=2

For CH3OH

This has only 1 covalent bond.

Therefore i=1

MOLALITY:

(NH4)3PO4 = 0.75M

CaSO4= 1.0M

LiCl= 1.0M

CH3OH= 1.5M

FREEZING POINT DEPRESSION:

For (NH4)3PO4

∆T= 4×0.75×1.86=5.58°C

For CaSO4

∆T= 2×1.0×1.86=3.72°C

For LiCl

∆T = 2×1.0×1.86= 3.72°C

For CH3OH

∆T= 1×1.5×1.86=2.79°C

REMEMBER THE HIGHER THE FREEZING POINT DEPRESSION THE LOWER THE FREEZING POINT.

FREEZING POINT DEPRESSION IS THE CHANGE IN THE FREEZING POINT PROPORTIONAL TO THE AMOUNT OF SOLUTE ADDED THE THE SOLUTION.

THEREFORE THE ONE WITH THE LOWEST FREEZING POINT IS (NH4)3PO4

4 0
4 years ago
The bond between metal ions and the sea of electrons
Vilka [71]

Answer: Metallic Bonding. ... In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

6 0
3 years ago
Can some one help with this question too??
ira [324]
Your answer is right tho
7 0
3 years ago
The pH value of 0.1 mol dm-3 of acid U is 1. Which statement is true about acid U?
lesya [120]

Answer:

the degree of ionization in water is high

Explanation:

The term pH is defined as the negative logarithm of hydrogen ion concentration.

Hence;

pH = -log[H^+]

The pH scale shows the degree of acidity or alkalinity of a solution. A solution of pH 1 is a strong acid. A strong acid dissociates completely in solution.

Hence, acid U has a high degree of ionization in water.

3 0
3 years ago
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