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3 years ago

Select the situation below that would produce a total displacement of zero

Chemistry

2 answers:

Arada [10]3 years ago

8 0

Answer:

where are the situations lol

likoan [24]3 years ago

6 0

Answer:

uhhhhhjjj??????????

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If the edge length of the unit cell is 705.2 pm, what is the density of KI in g/cm3.

Kipish [7]

The density is 3.144 g / cm^3.

Explanation:

If effective number of atom in NaCl type structure, z = 4

a = 705.2 pm ⇒ In centimeter = 705.2 $\times$ 10^-10

Na = 6.023 $\times$ 10^23

density = (molecular weight) (z) / (Na) (a^3)

where molecular weight of KI is 166 g,

Z represents the atomic number

density = (molecular weight) (z) / (Na) (a^3)

= (166 $\times$ 4) / (6.023 $\times$ 10^23) $\times$ (705.2 $\times$ 10^-10)

density = 3.144 g / cm^3.

5 0

3 years ago

Use the iupac nomenclature rules to give the name for this compound - n2o3.

wel

By use IUPAC nomenclature rule compound N2O3 is named as

Dinitrogen trioxide ( answer d)

Nitrogen (N2) is named before oxygen(O3) since they are arranged alphabetically. In addition the prefix Di is used infront of nitrogen since they are two nitrogen atoms while prefix tri is used infront of oxide since they are 3 oxygen atoms

8 0

2 years ago

Read 2 more answers

I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago

What is the empirical formula for glucose A) B) C) D)

pshichka [43]

The Answer is A CH2O

The molecular formula for glucose is C6H12O6. The subscripts represent a multiple of an empirical formula. To determine the empirical formula, divide the subscripts by the GCF of 6 which gives CH2O.

4 0

3 years ago

Read 2 more answers

Why is the mass of an iron atom different from the mass of a copper atom?

Jobisdone [24]

They have different number of Neutrons and protons, so their masses are different

Hope this helps!

6 0

3 years ago