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3 years ago

Select the situation below that would produce a total displacement of zero

Chemistry

2 answers:

Arada [10]3 years ago

8 0

Answer:

where are the situations lol

likoan [24]3 years ago

6 0

Answer:

uhhhhhjjj??????????

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Volume of 8.29ml and a mass of 16.31g

strojnjashka [21]

Density = mass/volume = 16.31/8.29 = 1.96 g/mL.

Hope this helps!

3 0

3 years ago

The _____ heats the earth. this creates convection currents in the _____ and ________. the heating of these areas create ______

andrew-mc [135]

Answer:

sun, air, water, wind and ocean current

Explanation:

As sun is the major source of energy on earth, the earth gets heated due to solar energy, this creates convection currents in the Air and Water, the heating of these areas create wind and ocean currents due to difference in temperature and pressure.

5 0

3 years ago

How many grams of water will absorb a total of 2400 joules of energy when the temperature changes from 10.0°C to 30.0°C?

Jobisdone [24]

Answer:

28.7 grams of water

Explanation:

Calorimetry problem:

Q = C . m . ΔT

2400 J = 4.18 J/g°C . m . (30°C - 10°C)

2400 J = 4.18 J/g°C . m . 20°C

2400J = 83.6 J/g . m

2400J / 83.6 g/J = m

28.7 g = m

8 0

2 years ago

Producers are generally found at the beginning of a food chain. Which

Firlakuza [10]

Explanation:

Second answer is the correct one.

8 0

2 years ago

Need help now

serg [7]

13 half-lives have passed

<h3>Further explanation </h3>

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

t1/2 = 4 days

Nt=18 mg (0.01% of the original isotope)

18 mg (Nt) = 0.01% No

No = the original isotope :

$\tt No=\dfrac{100}{0.01}\times 18~mg=180,000$

The duration of decay (T) :

$\tt \dfrac{Nt}{No}=\dfrac{1}{2}^{T/4}\rightarrow Nt=0.01\%No$

$\tt 0.01\%=\dfrac{1}{2}^{T/4}\\\\10^{-4}=\dfrac{1}{2}^{T/4}\\\\(\dfrac{1}{2})^{13}=\dfrac{1}{2}^{T/4}\\\\13=T/4\rightarrow T=52~days$

Half-lives passed :

$\tt \dfrac{52}{4}=13~half-lives$

3 0

2 years ago