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forsale [732]
3 years ago
13

15 pointsss please help meeeeeeeeeee

Physics
2 answers:
AveGali [126]3 years ago
5 0
A. Acceleration! ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ
Aleks04 [339]3 years ago
3 0

Answer:

the answer is A. acceleration mom

Explanation:

:)

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The table shows the potential energy and kinetic energy of a skier at two different positions on a hill.
Serggg [28]

Answer:

30,000 units, because total energy remains unchanged

6 0
3 years ago
Read 2 more answers
A foot spa machine is an electronic gadget used for soaking,bathing and massaging the feet.​
OverLord2011 [107]

Answer:

Just gonna take this at free points and yes you are right but I am confused on what you wanted us to do

4 0
3 years ago
A mass of 4.8 kg is dropped from a height of 4.84 meters above a vertical spring anchored at its lower end to the floor. If the
krek1111 [17]

Answer:

45.6 cm

Explanation:

Let x (m) be the length that the spring is compressed. We know that when we drop the mass from 4.84 m above and compress the springi, ts gravitational energy shall be converted to spring potential energy due to the law of energy conservation

E_g = E_p

mgh = 0.5kx^2

where h = 4.84 + x is the distance from the dropping point the the compressed point, and k = 24N/cm = 2400N/m is the spring constant, g = 9.81 m/s2 is the gravitational acceleration constant. And m = 4.8 kg is the object mass.

4.8*9.81(4.84 + x) = 0.5 * 2400 * x^2

47.088x + 227.906 = 1200x^2

1200x^2 - 47.088x - 227.906 = 0

x = 0.456m or 45.6 cm

5 0
4 years ago
Introduction: The specific heat capacity of a substance is the amount of energy needed to change the temperature of that substan
ki77a [65]

Answer:

A) 8,368 J

B) ) 0.893 J/gºC

Explanation:

A)

  • The heat gained by the water can be obtained solving the following equation:

       q_{g} = c_{w} * m *  \Delta T (1)

  • where cw = specific heat of water = 4.184 J/gºC
  • m= mass of water = 1,000 g
  • ΔT = 2ºC
  • Replacing these values in (1) we get:

       q_{g} = c_{w} * m *  \Delta T = 4.184 J/gºC*1,000 g* 2ºC = 8,368 J (2)

B)

  • Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative:  -8,368 J.
  • Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:

       q_{l} = c_{Al} * m_{Al} *  \Delta T  (3)

⇒    -8,368 J = c_{Al}* 125 g * (-74.95ºC) (4)

       c_{Al} = \frac{-8,368J}{125g*(-74.95ºC} = 0.893 J/gºC (5)

  • which is pretty close to the Aluminum's accepted specific heat value of 0.900 J/gºC.

8 0
3 years ago
( I will give a brainliest )
True [87]

Answer:

The answer is temperature lol

Explanation:

:)

4 0
3 years ago
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