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Nitella [24]
3 years ago
8

A copper cylinder, 12.0 cm in radius, is 44.9 cm long. If the density of copper is 8.90 g/cm^3, calculate the mass in grans of t

he cylinder. (Assume pi=3.14
Chemistry
1 answer:
zlopas [31]3 years ago
5 0

Answer:

we use: V = pi*(r^2)*h

V = 3.14*(12.0cm^2)*44.0 cm

V = 19895.04 cm^3

Therefore, mass = (8.90g/cm^3) * (19895.04 cm^3) = 177065.856 g

Explanation:

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How is an exothermic reaction identified on a potential energy diagram?
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Energy diagrams are use to depict the energy changes that occur during a chemical reaction. There are two types of reaction based on the energy change, these are exothermic and endothermic reactions. In endothermic reactions energy are gained while in exothermic reactions energy are lost to the environment. To identify an exothermic reaction on a potential energy diagram, one has to compare the potential energy of the reactants and the products. If the potential energy of the product is less than that of the reactants, the reaction is exothermic.
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3 years ago
A certain electromagnetic wave a wavelength of 415 nm. What is the frequency of the wave in hz?
Kaylis [27]

Answer:

The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz

Explanation:

The wavelength of the electromagnetic wave, λ = 415 nm

The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s

Given that an electromagnetic wave is a periodic wave, we have;

The speed of the electromagnetic wave, c = f×λ

Where;

f = The frequency of the electromagnetic wave

Therefore, we have;

f = c/λ

From which we have;

f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz

The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz

8 0
3 years ago
What is the average yearly rate of change of carbon-14 during the first 5000 years?
erica [24]

Answer:

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year

Explanation:

Given that the mass of the carbon 14 at the start = 5 gram

At the end of 5,000 years we will have;

A = A_0 \times e^{-\lambda \times t}

Where

A = The amount of carbon 14 left

A₀ = The starting amount of carbon 14

e = Constant = 2.71828

T_{1/2} = The half life

\lambda = 0.693/T_{1/2}

t = The time elapsed = 5000 years

λ = 0.693/T_{1/2} = 0.693/5730 = 0.0001209424

Therefore;

A = 5 × e^(-0.0001209424×5000) = 2.7312 grams

Therefore, the amount of carbon 14 decayed in the 5000 years is the difference in mass between the starting amount and the amount left

The amount of carbon 14 decayed = 5 - 2.7312 = 2.2688 grams

The average yearly rate of change of carbon-14 during the first 5000 years  is therefore;

2.2688 grams/(5000 years) = 0.0004538 grams per year

The average yearly rate of change of carbon-14 during the first 5000 years = 0.0004538 grams per year.

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