Question

The bond length in the HBr molecule is 1.41 Å. Calculate the dipole moments, in debyes, if the charges on the H and Br atoms were +1 and -1, respectively.

Answer 1

Answer:

The Dipole moment is 6.77 Debyes.

Explanation:

Given bond length of HBr molecule = 1.41 A°,

We also know charges on H and Br(+1 and -1 respectively)

Charge on H  =  (+1) $\times$ (absolute charge of electron);

Charge on Br  =  (-1) $\times$ (absolute charge of electron);

Since absolute charge on electron = $1.602\times 10^{-19}$;

Therefore charge on H = $1.602\times 10^{-19}$ Coulomb;

charge on Br = $-1.602\times10^{-19}$

We know Dipole Moment = Charge $\times$ Distance;

Here,

Distance = Bond Length = 1.41 A° = 1.41 $\times 10^{-10}$;

and charge on atom =  $1.602\times 10^{-19}$ Coulomb;

Therefore,

Dipole Moment =  Distance $\times$ Charge

Dipole Moment =  $1.41\times10^{-10} \times1.602\times10^{-19}$;

Dipole Moment =  $2.25882\times10^{-29}$ SI units.

The conversion factor of for SI units to Debye is 2.9989 $\times 10^{29}$

Therefore,

Dipole Moment = 2.25882 $\times 10^{-29}\times 2.9985\times10^{29}$

Dipole Moment = 6.77 Debye.