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Allisa [31]
3 years ago
9

A car engine supplies 2.0 x 103 joules of energy during the 10. seconds it takes to accelerate the car along a horizontal surfac

e. What is the average power
developed by the car engine while it is accelerating?
1. 2.0 x 10^1 w
2. 2.0 x 10^2 w
3. 2.0 x 10^3 W
4. 2.0 x 10^4 w
Physics
1 answer:
andrew11 [14]3 years ago
7 0

Answer: 2. 2.0*10^2 W

Explanation:

Power = Work/Time

Power = (2.0*10^3) Joules/10 seconds

Power = 2.0*10^2 Watts

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The force between two charged bodies is called ______________.
stepladder [879]

The Coulomb force between two or more charged bodies is the force between them due to Coulomb's law. If the particles are both positively or negatively charged, the force is repulsive; if they are of opposite charge, it is attractive. ... Like the gravitational force, the Coulomb force is an inverse square law.

6 0
4 years ago
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According to Bernoulli's equation, the pressure in a fluid will tend to decrease if its velocity increases. Assuming that a wind
Pie

Answer:

The pressure drop predicted by Bernoulli's equation for a wind speed of 5 m/s

= 16.125 Pa

Explanation:

The Bernoulli's equation is essentially a law of conservation of energy.

It describes the change in pressure in relation to the changes in kinetic (velocity changes) and potential (elevation changes) energies.

For this question, we assume that the elevation changes are negligible; so, the Bernoulli's equation is reduced to a pressure change term and a change in kinetic energy term.

We also assume that the initial velocity of wind is 0 m/s.

This calculation is presented in the attached images to this solution.

Using the initial conditions of 0.645 Pa pressure drop and a wind speed of 1 m/s, we first calculate the density of our fluid; air.

The density is obtained to be 1.29 kg/m³.

Then, the second part of the question requires us to calculate the pressure drop for a wind speed of 5 m/s.

We then use the same formula, plugging in all the parameters, to calculate the pressure drop to be 16.125 Pa.

Hope this Helps!!!

7 0
3 years ago
The word “virtual” refers to something that exists in effect but not in actual fact. How does this definition relate to the virt
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Because you see yourself the opposite way in a mirror. So yes your “seeing” yourself but not how everyone else sees you.
8 0
3 years ago
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A 0.6 kg basketball moving 7.2 m/s to the right collides with a 0.04 kg tennis
KonstantinChe [14]

Answer:

B

Explanation:

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A stationary 15 kg object is located in a table near the surface of the earth. The coefficient of static friction between the su
Marta_Voda [28]

The net force acting on the object perpendicular to the table is

∑ F[perp] = F[normal] - mg = 0

where mg is the weight of the object. Then

F[normal] = mg = (15 kg) (9.8 m/s²) = 147 N

The maximum magnitude of static friction is then

0.40 F[normal] = 58.8 N

which means the applied 40 N force is not enough to make the object start to move. So the object has zero acceleration and does not move.

8 0
2 years ago
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