Answer:
F = 37.8 × 10^(6) N
Explanation:
The charges are 0.06 C and 0.07 C.
Thus;
Charge 1; q1 = 0.06 C
Charge 2; q2 = 0.07 C
Distance between them; r = 3 m
Formula for the force in between them is;
F = kq1•q2/r²
Where k is a constant = 9 × 10^(9) N.m²/C²
Thus;
F = (9 × 10^(9) × 0.06 × 0.07)/3²
F = 37.8 × 10^(6) N
<h2>
Height of bridge is 83.66 m</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 25.3 m/s
Acceleration, a = 9.81 m/s²
Time, t = 2.29 s
Substituting
s = ut + 0.5 at²
s = 25.3 x 2.29 + 0.5 x 9.81 x 2.29²
s = 83.66 m
Height of bridge is 83.66 m
K (Q1) (Q2)/d^2 =
k : coulumb constant
Q1 : Charge on object 1
Q2 : Charge on object 2
d : distance between two charged object
Its very simple if a body is moving in circle the magnitude of its velocity remain constant but its direction changes because velocity is directed towards tangent and at every point in a cirlce its direction will be different (along tangent) so velocity is not uniform .As acceleration is the rate change of velocity so it will be non zero because velocity is changing due to its direction.
Answer:
241 kPa
Explanation:
The ideal gas law states that:
where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
We can rewrite the equation as
For a fixed amount of gas, n is constant, so we can write
Therefore, for a gas which undergoes a transformation we have
where the labels 1 and 2 refer to the initial and final conditions of the gas.
For the sample of gas in this problem we have
So we can solve the formula for 
, the final pressure:
