Answer:
2.01 M
Explanation:
Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)
The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.
![36.2g \times \frac{1mol}{60.05g} = 0.603mol](https://tex.z-dn.net/?f=36.2g%20%5Ctimes%20%5Cfrac%7B1mol%7D%7B60.05g%7D%20%3D%200.603mol)
Step 2: Convert the volume of solution to liters
We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)
![300mL \times \frac{1L}{1000mL} = 0.300L](https://tex.z-dn.net/?f=300mL%20%5Ctimes%20%5Cfrac%7B1L%7D%7B1000mL%7D%20%3D%200.300L)
Step 3: Calculate the molarity of the solution
The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution
![M = \frac{0.603mol}{0.300L} = 2.01 M](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B0.603mol%7D%7B0.300L%7D%20%3D%202.01%20M)
I don’t know what the question is asking
3 Mg, 0 Fe2O3, 3MgO, 2 Fe