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jonny [76]
3 years ago
9

1. As described by the first law of thermodynamics, the change in internal energy of a system is equal to _____.

Physics
2 answers:
Olegator [25]3 years ago
4 0

the first one is d

the second is c

slava [35]3 years ago
3 0
The first one is D
the second one is C
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The diagram shows the flow of water through a hydroelectric power station. The falling water
KonstantinChe [14]

Answer:

KE = \frac{1}{2} mv^{2}

Explanation:

In the generation of energy from hydroelectric power station, the motion of water, and the turbines are paramount. The falling flowing water turns the blades of the turbine, which in-turn causes the movement of a coil within a strong magnetic field.

The motion of the coil which cuts the strong magnetic field induces current. Thus, the system generates electrical energy.

The equation that links kinetic energy (KE), mass (m) and speed (v) can be expressed as:

KE = \frac{1}{2} mv^{2}

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From the frame of reference of car 1, what is the velocity of car 2?​
Ludmilka [50]

Answer:

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Explanation:

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3 years ago
A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.
mixas84 [53]
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
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Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s


8 0
2 years ago
Willing to give out Brainliest: 3.00 m^3 of water is at 20.0°C If you raise its temperature to 60.0°C, by how much will its volu
lozanna [386]

Answer:

The answer is below

Explanation:

Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:

V = kT, where V = volume and T = temperature, k = constant. Therefore:

V / T = k

\frac{V_1}{T_1}=\frac{V_2}{T_2}

Given that: V_1=3\ m^3, T_1=20^oC=(20 + 273)K=293\ k,T_2=60^oC=(60 + 273)K=333\ k.\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{3}{293}=\frac{V_2}{333}    \\\\V_2=\frac{3}{293}*333\\\\V_2=3.41\ m^3\\

The new volume is 3.41 m³. That is it expands by 0.41 m³

4 0
3 years ago
Read 2 more answers
Three identical springs each have the same spring constant k. if these three springs are attached end to end forming a spring th
wlad13 [49]
If the springs are connected together from end to end, they are arranged in series. For springs in series, the forces are additive. 

Spring 1: F1 = k1(Δx1)
Spring 2: F2 = k2(Δx2)
Spring 1: F3 = k3(Δx3)

Total Force = k1(Δx1)+k2(Δx2)+k3(Δx3)
Total Force = (k1+k2+k3)(Δx,total)

The spring constants are added together and multiplied with the total length of elongation to find the total force acting on it.
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