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3 years ago

What is the temperature dependency of the electrical conductivity for metals and semiconductors??

Engineering

1 answer:

geniusboy [140]3 years ago

3 0

Answer and Explanation:

TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF METALS : Metals are good conductors of electricity but when we increase the temperature the free electrons of metals collide with each other due to heat.There collision become very fast and so the resistance increases and so the electrical conductivity of metals decreases on increasing temperature.

TEMPERATURE DEPENDENCY ON ELECTRICAL CONDUCTIVITY OF SEMICONDUCTOR : The electrical conductivity of semiconductor is mainly sue to presence of impurities and defects as the temperature increases the impurities and defects also increases so the electrical conductivity of semiconductor increases on increasing temperature.

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At the instant shown car A is travelling with a velocity of 24 m/s and which is decreasing at 4 m/s2 along the highway. At the s

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(a) V(A/B) = (14 i - 17.32 J) m/s

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<u>Explanation:</u>

We will solve with respect to Cartesian vector form.

So,

V(A)= (24i) m/s

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The tangential acceleration, a(t) = 5 m/s²

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So,

$a(n) = \frac{(20)^2}{250}\\ \\a(n) = 1.6 m/s^2$

For the tangential acceleration, the acceleration is slowing down. So,

a(t) = (-5 cos 60° i - 5 sin 60° j ) m/s²

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For normal acceleration, it towards center. So,

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a(n) = (1.39 i - 0.8 j ) m/s²

Total acceleration of Car B:

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(a) V(A/B) = ?

V(A) = V(B) + V(A/B)

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V(A/B) = (14 i - 17.32 J) m/s

(b) acc(A/B) = ?

acc(A) = acc(B) + acc(A/B)

(4i) m/s² = (-1.11i - 5.13 j ) m/s² + acc(A/B)

acc(A/B) = ( 5.11 i + 5.13 j ) m/s²

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