an object is thrown off a cliff with intial pward velocity of 15m/s it strikes the ground with downward velocity of 25 m/s what
is the height of the cliff
1 answer:
Answer:
20 m
Explanation:
Given:
v₀ = 15 m/s
v = -25 m/s
a = -10 m/s²
Find: Δy
v² = v₀² + 2aΔy
(-25 m/s)² = (15 m/s)² + 2 (-10 m/s²) Δy
Δy = 20 m
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Answer:
v=500 m/s
<h3>Solution:</h3>
v=(10m)(50/s)
122
...................................................................,.......,..................................
<span>by vectors that are all the same length
</span>
M=3kg
p=33kg.m/s
p=m*v
v=p/m
=33/3
=11m/s
thus option (c)
Answer: Its a
Explanation:
