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ira [324]
3 years ago
11

an object is thrown off a cliff with intial pward velocity of 15m/s it strikes the ground with downward velocity of 25 m/s what

is the height of the cliff
Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

20 m

Explanation:

Given:

v₀ = 15 m/s

v = -25 m/s

a = -10 m/s²

Find: Δy

v² = v₀² + 2aΔy

(-25 m/s)² = (15 m/s)² + 2 (-10 m/s²) Δy

Δy = 20 m

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4 years ago
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The amplitude of a simple harmonic oscillator will be doubled by:a) doubling only the initial speedb) doubling the initial displ
OLEGan [10]

Answer:

When both initial speed and initial displacement is doubled then amplitude will be doubled.

Explanation:

Given that :- Amplitude of simple harmonic Oscillator  is doubled.

So,

     Formula of Simple harmonic oscillator is  X=A\sin\ (2\pi ft +\phi)  ...........(1)

                                                            Where X = Position in (m,cm,km.....)

                                                                        A = Amplitude  in (m,cm,km.....)

                                                                        F = Frequency in (Hz)

                                                                        T = Time in (sec.)

                                                                        Ф = Phase in (rad)

  For initial displacement taking t=0 we get,

                          Initial displacement = A\sin(\phi)    .................(2)            

Now taking equation (1) and differentiating it w.r.t to (t) we get

                                \frac{dx}{dt} = 2\pi fA\cos\ (2\pi ft+\phi)

                                 V= 2\pi fA\cos\ (2\pi ft+\phi)

taking t=0 for initial speed then we get,

                                Initial speed = 2\pi fA\cos\phi    ...............(3)

observing equation (2) & (3) that the initial displacement and initial speed depends on the Amplitude of the Oscillator.

Hence,

when both initial speed and displacement is doubled then amplitude will be doubled.

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