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ira [324]
3 years ago
11

an object is thrown off a cliff with intial pward velocity of 15m/s it strikes the ground with downward velocity of 25 m/s what

is the height of the cliff
Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

20 m

Explanation:

Given:

v₀ = 15 m/s

v = -25 m/s

a = -10 m/s²

Find: Δy

v² = v₀² + 2aΔy

(-25 m/s)² = (15 m/s)² + 2 (-10 m/s²) Δy

Δy = 20 m

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A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of
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Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

                                            = 6.24151× 10²¹ MeV/s

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\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}

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                                       =5.94 × 10¹⁹× 24 × 60 ×60)

                                      =  5.13 × 10²⁴ fission/day

mu = 235.04393 ×  1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

   = 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M   =  2 kg(approx.)

mass consumed by 235U each day = 2 kg

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The equation P^xV^yT^z= constant is Boyle law for what is the values of x,y,z​
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