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babymother [125]
3 years ago
15

The most common substance on earth is water. True Or False

Chemistry
1 answer:
shtirl [24]3 years ago
4 0
True... water and land mostly covers up the earth... go anywhere and there is water...
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Describe how urine is removed from the blood and then eliminated from the body
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Passes through the kidneys and the good stuff is kept, and the other stuff is passed through leading to the bladder.  The once the bladder is full enough to send the message to the brain, urine (waste) is eliminated from the body.
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After throwing the ball in the pool for my dog the ball sprung a leak and begin to fill with water. How many mL of water can th
ikadub [295]

Answer: i think 250ML

Explanation:

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Methods scientists use to determine if a change was physical or chemical.
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Chemical reactions can be identified when there is a change in color, energy is produced, change in odor, or if new substance forms.
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Read 2 more answers
A reduction reaction involves either the addition of hydrogen or removal of:
Marina CMI [18]

Reduction involves the either the addition of hydrogen and removal of oxygen.

<h3>What is reduction?</h3>

Reduction involves the removal of oxygen.

This implies there is a loss of oxygen in reduction.

This can be represented in the extraction of iron from it ores.

Fe₂O₃ + 3CO →  2Fe + 3CO₂

Reduction is also the addition of hydrogen. This implies it is the gain of hydrogen.

For example

CH₃CHO → CH₃CH₂OH

learn more on reduction here: brainly.com/question/9485345

#SPJ12

4 0
2 years ago
Write a balanced equation for the complete oxidation reaction that occurs when ethane burns in air
damaskus [11]
<h3>Balanced equation : 2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>

Alkanes are saturated hydrocarbons that have single bonds in chains

General formula for alkanes :

\tt \large{\bold{C_nH_{2n+2}}

Hydrocarbon combustion reactions (specifically alkanes)

\large {\box {\bold{C_nH _ (_2_n _ + _ 2_) + \dfrac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}

So that the burning of ethane with air (oxygen):

\tt C_2H_6+\dfrac{7}{2}O_2\rightarrow 2CO_2+3H_2O

2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)

or we can use mathematical equations to solve equilibrium chemical equations by giving the coefficients for each compound involved in the reaction

C₂H₆ (g) + aO₂ (g) ⟶ bCO₂ (g) + cH₂O (ℓ)

C : left 2, right b ⇒ b=2

H: left 6, right 2c⇒ 2c=6⇒ c= 3

O : left 2a, right 2b+c⇒ 2a=2b+c⇒2a=2.2+3⇒2a=7⇒a=7/2

6 0
3 years ago
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