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riadik2000 [5.3K]
3 years ago
14

What would be the required voltage of an energy source in a circuit with a current of 10.0 A and a resistance of 11.0 Ω?

Engineering
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

  110 V

Explanation:

V = IR

V = (10.0 A)(11.0 Ω) = 110 volts

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With which type of media are you interacting when you read an online shopping website? A. film B. print C. electronic D. social
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A. film

B. print

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<h3><u>D. social </u><u>media</u></h3>

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8 0
2 years ago
The specific grounding and bonding requirements for an information technology room are located in which article of the nec?
Oksi-84 [34.3K]

The specific grounding and bonding requirements for an information technology room are located in Article 645.

<h3>What does NEC stand for?</h3>

The National Electrical Code (NEC) is a collection of requirements for the secure installation of electrical wiring in the US that are routinely updated.

Bonding is the joining of conductors that do not convey current, such as enclosures and buildings. Bonded systems are attached to the earth by grounding. To protect persons and property from electric risks, both are required.

Article 645 compliance is optional. The two main pardons provided by Article 645 are. First, underneath a raised floor, non-plenum-rated cables are acceptable. Second, cables, boxes, and similar items for the mentioned IT equipment are exempt from the need for security. sted IT equipment cables, boxes, and the like are not required to be secured in place.

To learn more about NEC refer to:

brainly.com/question/20348027

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6 0
2 years ago
A thin-walled tube with a diameter of 6 mm and length of 20 m is used to carry exhaust gas from a smoke stack to the laboratory
Molodets [167]

Answer:

Explanation:

Mean temperature is given by

T_mean = \frac{T_i + T_ \infinity}{2}\\\\T_mean = \frac{200 + 15}{2}

Tmean = (Ti + T∞)/2

T_mean = 107.5^{0}

Tmean = 107.5⁰C

Tmean = 107.5 + 273 = 380.5K

Properties of air at mean temperature

v = 24.2689 × 10⁻⁶m²/s

α = 35.024 × 10⁻⁶m²/s

\mu = 221.6 × 10⁻⁷N.s/m²

\kappa = 0.0323 W/m.K

Cp = 1012 J/kg.K

Pr = v/α  = 24.2689 × 10⁻⁶/35.024 × 10⁻⁶

              = 0.693

Reynold's number, Re

Pv = 4m/πD²

where Re = (Pv * D)/\mu

Substituting for Pv

Re = 4m/(πD\mu)

     = (4 x 0.003)/( π × 6 ×10⁻³ × 221.6 × 10⁻⁷)

     = 28728.3

Since Re > 2000, the flow is turbulent

For turbulent flows, Use

Dittus - Doeltr correlation with n = 0.03

Nu = 0.023Re⁰⁸Pr⁰³ = (h₁D)/k

(h₁ × 0.006)/0.0323 = 0.023(28728.3)⁰⁸(0.693)⁰³

(h₁ × 0.006)/0.0323 = 75.962

h₁ = (75.962 × 0.0323)/0.006

h₁ = 408.93 W/m².K

4 0
3 years ago
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