Answer:
Explanation:
Given
Velocity of jet relative to the carrier
Velocity of jet carrier to the wind
Velocity of wind
Length of runway=126 m
thus =20.11+8.94=29.05
=29.05+45=74.05 m/s
to find acceleration
here u=0,v=74.05 m/s
case -2
Velocity of jet relative to the carrier
Velocity of jet carrier to the wind
Velocity of wind
Length of runway=126 m
here u=0,v=77.7 m/s
Answer:
The warm seas create a large humid air mass. The warm air rises and forms a low pressure cell, known as a tropical depression.
Explanation:
Hurricanes arise in the tropical latitudes (between 10 degrees and 25 degrees N) in summer and autumn when sea surface temperature are 28 degrees C (82 degrees F) or higher.
1. stone
s=9,5m
a=g≈10m/s²
t1=?
s=(at²)/2
2s=at²
2s/a=t²
t=√(2s/a)=√(2*9.5m/10m/s²)=√(1,9s²)≈1,38s
2. sound
s=9,5m
V=343m/s²
t2=?
V=s/t
Vt=s
t=s/V=9,5m/343m/s≈0,03s
-------------------------------------------------
V1+V2=1,38s+0,03s=1,41s
"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."
Regards M.Y.
solution:
As Given plane is flying in east direction.
It throws back some supplies to designated target.
Time taken by the supply to reach the target =10 seconds
g = Acceleration due to gravity = - 9.8 m/s²[Taken negative as object is falling Downwards]
As we have to find distance from the ground to plane which is given by d.
d =
= meters
Distance from the ground where supplies has to be land to plane = Option B =490 meters
Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
Lens equation
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.