Answer:
Mars.
Explanation:
It only has a little over 24 hours in a day, its rotation axis is tilted about the same as earths, and I MAY actually have some water on its surface.(Though none has been discovered YET)
Hope this helps lots and lots,
sincerely, me
When the balloon is kept in the sun, due to Sun's heat, the kinetic energy of gaseous particles inside the balloons also gets increased and the balloon expands. This will increase the pressure on the walls of the balloon. It continues to expand and comes to a stage when the baloon bursts.
Answer:
Tables, with their rows and columns of data, interact primarily with our verbal system. We read tables. ... Tables are also handy when you have many different units of measure, which can be difficult to pull off in an easy to read manner in a graph. Graphs, on the other hand, interact with our visual system.
Answer:
Two possible points
<em>x= 0.67 cm to the right of q1</em>
<em>x= 2 cm to the left of q1</em>
Explanation:
<u>Electrostatic Forces</u>
If two point charges q1 and q2 are at a distance d, there is an electrostatic force between them with magnitude
![\displaystyle f=k\frac{q_1\ q_2}{d^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%3Dk%5Cfrac%7Bq_1%5C%20q_2%7D%7Bd%5E2%7D)
We need to place a charge q3 someplace between q1 and q2 so the net force on it is zero, thus the force from 1 to 3 (F13) equals to the force from 2 to 3 (F23). The charge q3 is assumed to be placed at a distance x to the right of q1, and (2 cm - x) to the left of q2. Let's compute both forces recalling that q1=1, q2=4q and q3=q.
![\displaystyle F_{13}=k\frac{q_1\ q_3}{d_{13}^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B13%7D%3Dk%5Cfrac%7Bq_1%5C%20q_3%7D%7Bd_%7B13%7D%5E2%7D)
![\displaystyle F_{13}=k\frac{(q)\ (q)}{x^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B13%7D%3Dk%5Cfrac%7B%28q%29%5C%20%28q%29%7D%7Bx%5E2%7D)
![\displaystyle F_{23}=k\frac{q_2\ q_3}{d_{23}^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B23%7D%3Dk%5Cfrac%7Bq_2%5C%20q_3%7D%7Bd_%7B23%7D%5E2%7D)
![\displaystyle F_{23}=k\frac{(q)(4q)}{(0.02-x)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B23%7D%3Dk%5Cfrac%7B%28q%29%284q%29%7D%7B%280.02-x%29%5E2%7D)
![\displaystyle F_{23}=\frac{4k\ q^2}{(0.02-x)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B23%7D%3D%5Cfrac%7B4k%5C%20q%5E2%7D%7B%280.02-x%29%5E2%7D)
Equating
![\displaystyle F_{13}=F_{23}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F_%7B13%7D%3DF_%7B23%7D)
![\displaystyle \frac{K\ q^2}{x^2}=\frac{4K\ q^2}{(0.02-x)^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BK%5C%20q%5E2%7D%7Bx%5E2%7D%3D%5Cfrac%7B4K%5C%20q%5E2%7D%7B%280.02-x%29%5E2%7D)
Operating and simplifying
![\displaystyle (0.02-x)^2=4x^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%280.02-x%29%5E2%3D4x%5E2)
To solve for x, we must take square roots in boths sides of the equation. It's very important to recall the square root has two possible signs, because it will lead us to 2 possible answer to the problem.
![\displaystyle 0.02-x=\pm 2x](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.02-x%3D%5Cpm%202x)
Assuming the positive sign
:
![\displaystyle 0.02-x= 2x](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.02-x%3D%202x)
![\displaystyle 3x=0.02](https://tex.z-dn.net/?f=%5Cdisplaystyle%203x%3D0.02)
![\displaystyle x=0.00667\ m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D0.00667%5C%20m)
![x=0.67\ cm](https://tex.z-dn.net/?f=x%3D0.67%5C%20cm)
Since x is positive, the charge q3 has zero net force between charges q1 and q2. Now, we set the square root as negative
![\displaystyle 0.02-x=-2x](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.02-x%3D-2x)
![\displaystyle x=-0.02\ m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D-0.02%5C%20m)
![\displaystyle x=-2\ cm](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D-2%5C%20cm)
The negative sign of x means q3 is located to the left of q1 (assumed in the origin).