Answer:
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The initial speed of the bolt is not 58.86 m/s.
Let a be the acceleration of the rocket.
During the 4 sec lift off, the rocket has reached a height of
h = (1/2)*a*t^2
with t=4,
h = (1/2)*a^16
h = 8*a
Its velocity at 4 sec is
v = t*a
v = 4*a
The initial velocity of the bolt is thus 4*a.
During the 6 sec fall, the bolt has the initial velocity V0=-4*a and it drops a total height of h=8*a. From the equation of motion,
h = (1/2)*g*t^2 + V0*t
Substituting h0=8*a, t=6 and V0=-4*a into it,
8*a = (1/2)*g*36 - 4*a*6
Solving for a
a = 5.52 m/s^2
1. Ask a question
2. Form a hypothesis
3. Experiment
4.Record data
5.Draw Conclusion
6. Share Results
Answer:
b) Rs.901 is the selling price
Explanation:
selling price = cost price+profit percentage/100 x cost price
cost price = 850
profit percentage = 6%
selling price = 850+6/100 x 850 = 901
soln 2
if 100 % = 850
therefore what about 106% = ?
106 x 805/100 = 901
ans = 901
if you need any clarification or more explanation pls do mention on the comment section.i would like to help more
Hope this helps and if it does mark as branliest answer thx
The orbital with the lowest energy is 3s.
