Question

What volume would 0.435 moles of hydrogen gas, h2, occupy at stp?

Answer 1

The conversion factor for volume at STP is $\frac {1mol}{22.4L}$ or $\frac {22.4L}{1mol}$. Since we want volume, we would use $\frac {22.4L}{1mol}$. We conclude with the following calculations:

$0.435mol H_{2} * \frac {22.4LH_{2}}{1molH_{2}} = 9.744L$

The answer is 9.744L H2

Answer 2

Answer: The volume occupied by 0.435 moles of $H_2$ will be 9.7 Liters.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

Thus if 1 mole of $H_2$  occupies 22.4 L at STP

0.435 moles of $H_2$  occupies=$\frac{22.4}{1}\times 0.435=9.8L$ L at STP

The volume occupied by 0.435 moles of $H_2$ will be 9.7 Liters.