Sulfur dioxide gas reacts with oxygen gas for form sulfur trioxide gas. the equilibrium constant for the reaction at 6000c is 4. 34. an equilibrium mixture is found to have [so3] = 0.391 m and [o2] = 0.125 m at 6000c. what is the concentration of sulfur dioxide?
1 answer:
When the balanced equation for this reaction is: 2SO3 → 2SO2 + O2 so, by using ICE table: initial 0.391 0 0.125m change -X +2X +X Equ (0.391-X) 2X 0.125+X when Keq = concentration of products / concentration of reactants so, by substitution 4.34 = [2X]^2 * [0.125+X] / [0.391-X]^2 by solving for X ∴ X = 0.357 m ∴ the concentration of SO2 = 2x = 2 * 0.357 = 0.714 m
You might be interested in
The products. Without a balanced chemical equation, there is no reaction that can take place. The products is the final reation and the reactants help the final reaction take place.
Period are going left to right across the periodic table Groups are going up to down on the periodic table
Moves from the atmosphere to the oceans
Answer: Arsenic has five valence electrons.
Explanation: Good luck!
Lead fluoride hope this helps