If you take 3s to do 72J of work, how much power did you exert?
1 answer:
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Answer:
S = 4.08 m/s
Explanation:
given,
initial speed, v = 20.5 m/s
angle made with horizontal, θ = 45°
Distance of player = 55 m
Average speed of the player to catch the ball = ?
vertical velocity of the ball =
v_y = v sin θ = 20.5 x sin 45° = 14.5 m/s
horizontal velocity of the ball
v_x = v cos θ = 20.5 x cos 45° = 14.5 m/s
time taken by the ball to reach at the highest point
v = u + g t
v = V_y - g t
0 = 14.5 - 9.8 x t
t = 1.48 s
total time of flight = 2 t = 1.48 x 2 = 2.96 s
Horizontal distance travel by the ball
s = vₓ x t
s = 14.5 x 2.96
s = 42.96 m
distance player has to run
D = 55 - 42.96 = 12.08 m
Average speed of the player
S = 4.08 m/s
Speed of the player is equal to 4.08 m/s