A. Protons, neutrons, and electrons
The transition of an electron from an excited energy state to the ground state always results in B. the emission of electromagnetic radiation.
The electron is going from a high-energy state to one of low energy, so it emits this excess energy as electromagnetic radiation. This <em>may be visib</em>le light, but it <em>may also not be visible</em> to our eyes.
Answer : The energy required is, 574.2055 KJ
Solution :
The conversions involved in this process are :
Now we have to calculate the enthalpy change or energy.
![\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bm%5Ctimes%20c_%7Bp%2Cs%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2Bn%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
= energy required = ?
m = mass of ice = 1 kg = 1000 g
= specific heat of solid water = 
= specific heat of liquid water = 
n = number of moles of ice = 
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
Now put all the given values in the above expression, we get
![\Delta H=[1000g\times 4.18J/gK\times (0-(-10))^oC]+55.55mole\times 6010J/mole+[1000g\times 2.09J/gK\times (95-0)^oC]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B1000g%5Ctimes%204.18J%2FgK%5Ctimes%20%280-%28-10%29%29%5EoC%5D%2B55.55mole%5Ctimes%206010J%2Fmole%2B%5B1000g%5Ctimes%202.09J%2FgK%5Ctimes%20%2895-0%29%5EoC%5D)
(1 KJ = 1000 J)
Therefore, the energy required is, 574.2055 KJ
Answer: c if im wrong then b if im wrong i dont know what to tell ya
Explanation:
Answer:
placing a glass bottle in the recycling bin is what i think.
Explanation:
