What type of disease transmission is most likely represented by the graph shown belon

balandron [24]

#48 might be (A) but in not for sure

3 0

3 years ago

A balloon inflated in a room at 25oC has a volume of 3.00 L. If the balloon is heated at a constant pressure, at what temperatur

Alexeev081 [22]

Answer:

596K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 3.00 L

V2 = double of V1 = 2 × 3.00 = 6.00 L

T1 = 25°C = 25 + 273 = 298K

T2 = ?

Using V1/T1 = V2/T2

3/298 = 6/T2

Cross multiply

298 × 6 = 3 × T2

1788 = 3T2

T2 = 1788 ÷ 3

T2 = 596K

8 0

3 years ago

Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev

liq [111]

Answer: There will be 131.3 tons of $SO_{2}$ that will be generated.

Explanation : We have the data as 72 tons of $H_{2}S$ , $O_{2}$ is 101 tons and $H_{2}O$ as 38 tons.

Conversion of 1 ton to kg will be approximately 907.2 Kg

We have to convert the given data of tons into kg for all;

So, moles of $H_{2}S$ = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X $10^{6}$ moles

Now, moles of $O_{2}$ = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X $10^{6}$ moles

And, $H_{2}O$ = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X $10^{6}$ moles

Now, we have to calculate the moles of $H_{2}S$

so, 1.916 X $10^{6}$ moles / 2 moles of $H_{2}S$ = 958 X $10^{3}$

Now, for $O_{2}$ ;

So, 2.80 X $10^{6}$ moles / 3 moles of $O_{2}$ = 933.3 X $10^{3}$ moles

Here, we can see that $O_{2}$ is acting as a limiting reactant.

Now, moles of $SO_{2}$ = 2.80 X $10^{6}$ X (2 moles of $SO_{2}$ / 3 moles of $O_{2}$ ) = 1.86 X $10^{6}$

Now converting this into mass,

Mass = Moles X Molar Mass

Mass = 1.86 X $10^{6}$ X (64.066 g/mol X $10^{-3}$ kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of $SO_{2}$

7 0

3 years ago

Read 2 more answers

Are metal and non-metal elements typically ionically bonded? Explain.

victus00 [196]

Answer: Yes, metals and non-metals forms ionic bonds.

Explanation:

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

For Example: Formation of sodium chloride

Sodium is a metal and is the 11th element of periodic table having electronic configuration of $[Ne]3s^1$

To form $Na^{+}$ ion, this element will loose 1 electron.

Chlorine is a non-metal and is the 17th element of periodic table having electronic configuration of $[Ne]3s^23p^5$ .

To form $Cl^{-}$ ion, this element will gain 1 electron.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the compound formed between sodium and chlorine atom is NaCl

Hence, metals and non-metals forms ionic bonds.

8 0

3 years ago

The rule of eight chemistry

leva [86]

Answer:

octet rule

Explanation:

It refers to the tendency of atoms to prefer to have eight electrons in the valence shell.

3 0

3 years ago