We need to set up an I.C.E chart as follows:
CO H20 CO2 H2
<span>I 0.35 0.40 0 0 </span>
<span>C .35-x 0.40-x x x </span>
<span>E 0.19 0.40-x x x
</span>
We have 0.35 mol of CO at the start and 0.19 remaining. This means that x=0.35-0.19 >> 0.16
<span>Now substitute in 0.16 in your Ke equation. </span>
<span>Just in case you're having trouble with that: </span>
<span>Kb= [Products]/[Reactants] = ([CO][H2O])/([CO2][H2])
</span>
Therefore, the constant of equilibrium would be equal to 0.56.
Answer:
Option b is correct.
Explanation:
When
is dissolved in water,
and
are formed.

As
is an weak base and
is a strong acid, the resulting solution will be acidic in nature.
if K_b value is known, then pH of the solution can also be determined which will support prediction.
However, acidic and basic nature of the solution can be predicted without K_b value also.
So, among the given option, (b) is correct.
Answer:
40 mL
Explanation:
Volume=400g/10(g/mL)
= 40mL
hope this will help you ❤️
a. Negative
Explanation:
We have to look at its oxidation (burning, explosion) of TNT:
4 C₇H₅N₃O₆ + 21 O₂ → 28 CO₂ + 10 H₂O + 6 N₂ + heat
So trinitrotoluene need more oxygen atoms that is have to be fully oxidized so the oxygen balance will be negative.
An empirical formula with which you calculate the oxygen balance percent (OB %) is:
OB % = (-1600 / molecular wight) × [2X + (Y/2) + M - Z)
were
X = number of carbon atoms
Y = number of hydrogen atoms
M = number of metal atoms
Z = number of oxygen atoms
For TNT:
OB % = (-1600 / 227.13) × [2×7 + (5/2) + 0 - 6)
OB % = -73.97 %
So the oxygen balance percent is negative.
Learn more about:
oxidation of TNT
brainly.com/question/4427298
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Answer:
a = -2.4 ms⁻²
Explanation:
Given data:
Initial velocity of car = 37.1 m/s
Final velocity of car = 29.8 m/s
Time taken to change velocity = 3 sec
Acceleration of car = ?
Solution:
Formula:
a = Vf - V₀ / t
Vf = Final velocity
V₀ = Initial velocity
a = acceleration
t = time taken to change velocity
Now we will put the values in formula.
a = 29.8 m/s - 37.1 m/s / 3 s
a = -7.3 m/s/ 3s
a = -2.4 ms⁻²
Negative sign show that car is slowing down.