Answer:
-414.96 N
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
![v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20a%3D%5Cfrac%7Bv%5E2-u%5E2%7D%7B2s%7D%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B0%5E2-3.85%5E2%7D%7B2%5Ctimes%200.75%7D%5C%5C%5CRightarrow%20a%3D-9.88%5C%20m%2Fs%5E2)
![F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5CRightarrow%20F%3D42%5Ctimes%20-9.88%5C%5C%5CRightarrow%20F%3D-414.96%5C%20N)
The force the ground exerts on the parachutist is -414.96 N
If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase
Answer:
The metal will melt but their will be no change in temperature.
Explanation:
The metal is at its melting temperature which means it is still in solid phase but have to cross the enthalpy of its condensation at this same temperature to convert into liquid phase.
<u>On supplying heat, the metal's temperature will not change as the heat will be required as enthalpy of condensation to melt the solid to liquid at the melting temperature.</u>
I believe there should be some sort of table attached. Unfortunately I cannot answer this question. Sorry!