Ask question

Ask question

All categories

3 years ago

9

What is the balanced equation of iron (iii) hydrogen carbonate?

1 answer:

Lynna [10]3 years ago

6 0

<h3>Answer:</h3>

2Fe(HCO₃)₃ → Fe₂(CO₃)₃ + 3H₂O + 3CO₂

<h3>Explanation:</h3>

A decomposition reaction is one in which a large compound is broken down into smaller compounds or individual elements.
The decomposition reaction Iron (iii) hydrogen carbonate yield iron (iii) carbonate, water and carbon dioxide.

Fe(HCO₃)₃ → Fe₂(CO₃)₃ + H₂O + CO₂

A balanced equation is the one in which the number of atoms of each element are equal on both side of the equation.

Therefore; the balanced equation for the decomposition of Iron (iii) hydrogen carbonate is given by;

2Fe(HCO₃)₃ → Fe₂(CO₃)₃ + 3H₂O + 3CO₂

You might be interested in

The combustion of ethanol ( C 2 H 6 O) produces

nika2105 [10]

Answer:

C2H6O + 3O2 —> 2CO2 + 3H2O

Explanation:

7 0

3 years ago

Read 2 more answers

the spectral lines observed for hydrogen arise from transitions from excited states back to the n=2 principle quantum level. Cal

Sunny_sXe [5.5K]

Rydberg formula is given by:

$\frac{1}{\lambda } = R_{H}\times (\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} )$

where, $R_{H}$ = Rydberg constant = $1.0973731568508 \times 10^{7} per metre$

$\lambda$ = wavelength

$n_{1}$ and $n_{2}$ are the level of transitions.

Now, for $n_{1}$ = 2 and $n_{2}$ = 6

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{6^{2}} )$

= $1.0973731568508 \times 10^{7} \times (\frac{1}{4}-\frac{1}{36} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0278 )$

= $1.0973731568508 \times 10^{7} \times 0.23$

= $0.2523958\times 10^{7}$

$\lambda = \frac{1}{0.2523958\times 10^{7}}$

= $3.9620\times 10^{-7} m$

= $396.20\times 10^{-9} m$

= $396.20 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 5

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{5^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.04 )$

= $1.0973731568508 \times 10^{7} \times (0.21 )$

= $0.230 \times 10^{7}$

$\lambda= \frac{1}{0.230 \times 10^{7}}$

= $4.3478 \times 10^{-7} m$

= $434.78\times 10^{-9} m$

= $434.78 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 4

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{4^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0625 )$

= $1.0973731568508 \times 10^{7} \times (0.1875 )$

= $0.20575 \times 10^{7}$

$\lambda= \frac{1}{0.20575 \times 10^{7}}$

= $4.8602 \times 10^{-7} m$

= $486.02 \times 10^{-9} m$

= $486.02 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 3

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{3^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.12 )$

= $1.0973731568508 \times 10^{7} \times (0.13 )$

= $0.1426585\times 10^{7}$

$\lambda= \frac{1}{0.1426585\times 10^{7}}$

= $7.0097 \times 10^{-7} m$

= $700.97 \times 10^{-9} m$

= $700.97 nm$

5 0

3 years ago

Read 2 more answers

___ is anything that has mass and volume<br>Pls help

aliina [53]

Matter is anything that has mass and volume

8 0

3 years ago

Read 2 more answers

A teacher performs a flame test lab experiment for various compounds. During the lab, the teacher mislabels one of the solutions

nexus9112 [7]

Answer: By performing the flame test

Explanation:

The flame test can be performed by the teacher to visually identify the substance in the solution. The metals give a characteristic color on burning. The heat of the flame causes the excitation of the electrons present in the metal ions this leads to release of energy along with the emission of visible wavelength of light. This visible light can be observed by human eye. For example, the copper produces the blue color in flame, barium gives green flame, and sodium gives yellow flame.

4 0

2 years ago

Is sugar a compound or a mixture?

puteri [66]

Answer:

compound

Explanation:

3 0

2 years ago

Read 2 more answers