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k0ka [10]
3 years ago
7

At what point does sucrose actually become dissolved in the water?

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
Yes it does dissolve hope this helps
You might be interested in
Type the correct answer in the box.
Murljashka [212]

Answer:

<em>a= In scientific notation</em>

6.96×10⁵ Km

<em>b =In  expanded notation</em>

0.00019 mm

Explanation:

Given data:

Radius of sun = 696000 Km

size of bacterial cell = 1.9 ×10⁻⁴ mm

Radius of sun in scientific notation = ?

Size of bacterial cell in expanded notation = ?

Solution:

Radius of sun:

696000 Km

<em>In scientific notation</em>

6.96×10⁵ Km

Size of bacterial cell:

1.9 ×10⁻⁴ mm

<em>In  expanded notation</em>

1.9/ 10000 = 0.00019 mm

8 0
3 years ago
Is this a correct response? Please help me!
tia_tia [17]
Yes bsjaibsvdnakiebdnsoehdbdnsieveb
4 0
3 years ago
Read 2 more answers
Define Acid and alkalis​
kicyunya [14]

Answer:

Acids have a pH less than 7. Acids contain lots of hydrogen ions

Alkalis have a pH greater than 7. Alkalis contain lots of hydroxide ions

<u><em></em></u>

<u><em>Please mark as brainliest if answer is right </em></u>

Have a great day, be safe and healthy  

Thank u  

XD

7 0
3 years ago
Read 2 more answers
I don't know how to solve this​
Misha Larkins [42]

For the first part, use the question M=mol/vol (liters)

To do this, you have the given 1.6 M solution

divide the 360g by the molar mass of ethanol (44.07) to get moles

360/44.07=8.16 mol

so

1.6M = 8.16 mol/x vol

volume: 5.1 Liters

8 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
3 years ago
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