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Vedmedyk [2.9K]

4 years ago

10

A voltaic cell with Mn/Mn2+ and Cd/Cd2+ half-cells has the following initial concentrations: [Mn2+]= 0.090 M; [Cd2+] = 0.060 M.

(a) What is the initial E cell ?

1 answer:

larisa86 [58]4 years ago

4 0

Answer:

Initial Ecell = 0.78V

Explanation:

From the question, we get;

(Cd)2+) + Mn ---> Cd + (Mn2+)

We will check half cell potentials from the table attached, we get ;

Mn = - 1.18V and Cd = - 0.4V

Ecell (standard) = E(reduction) - E(oxidation) = - 0.4 - (-1.18) = 0.78V

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We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top

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We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

$F_D = c_D A \frac{\rho V^2}{2}$

Where,

F_D = Drag Force

$c_D$ = Drag coefficient

A = Area

$\rho$ = Density

V = Velocity

Our values are given by,

$c_D = 0.5$ (That is proper of a cone-shape)

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Part A ) Replacing our values,

$F_D = 0.5*9*\frac{1.2*6.5^2}{2}$

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3 years ago

What keeps the balanced rock balanced

pogonyaev

Hello,

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If you need anymore help feel free to ask me!

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3 years ago

Two automobiles traveling at right angles to each other collide and stick together. Car A has a mass of 1200 kg and had a speed

sergij07 [2.7K]

Answer:

$v_{B0}=15.73 m/s$

Explanation:

We can use the conservation of momentum. The initial momentum is equal to the final momentum:

x-coordinate

$p_{0x}=p_{fx}$

$m_{A}v_{A0}=(m_{A}+m_{B})v_{cx}$

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y-coordinate

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We can divide equations (2) and (1):

$\frac{m_{B}v_{B0}}{m_{A}v_{A0}}=\frac{sin(40)}{cos(40)}$

$\frac{m_{B}v_{B0}}{m_{A}v_{A0}}=tan(40)$

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4 years ago

Read 2 more answers

A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note

shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

The ball is thrown straight upward with initial velocity u

The ball reaches a maximum height of 4.5 m

At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is <em>v² = u² + 2ah</em>, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

⇒ 0 = u² - 88.2

Add 88.2 to both sides

⇒ 88.2 = u²

Take square root for both sides

⇒ u = 9.39 m/s

<em>The initial velocity was 9.39 m/s</em>

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4 years ago