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Pavlova-9 [17]
3 years ago
10

Explain the difference between statically determinate beam and statically in determinate beam with sketch.

Engineering
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer

Statically determinate beams are those beams in which the unknown reaction forces are equal or less than the equilibrium equation.

As shown in figure 1 in which reaction forces are 3 and we have 3 equilibrium equation so beam is determinate.

Statically indeterminate beams are those beams in which unknown reaction force are more than the  equilibrium equation.

As shown in figure 2 in which reaction forces are 6 and we have 3 equilibrium equation so beam is indeterminate.

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Almost done

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3 years ago
How many hours should I charge a 4.8v 600mah battery (I need it by today please)
prohojiy [21]

The number of hours that will be needed to charge a 600mah battery will be 1.5 hours.

<h3>What is a battery?</h3>

It should be noted that an electric battery simply means a source of electric power that consist of one or more electrochemical cells that are with external connections that are important for powering electrical devices.

It should be noted that when a battery is supplying power, then the positive terminal is the cathode while the negative terminal is the anode.

In conclusion, the number of hours that will be needed to charge a 600mah battery will be 1.5 hours.

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2 years ago
The results of a _________ test will determine if there is suitable drainage and the size of the drain field that will be requir
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The results of a percolation test will determine if there is suitable drainage and the size of the drain field that will be required for a septic system.

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2 years ago
For each resource, list 3 examples of how it would be used to produce a hamburger. Think outside of the “hamburger” box!
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3 years ago
Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at 1400 K and rejects th
Aleksandr-060686 [28]

Answer:

The temperature T= 648.07k

Explanation:

T1=input temperature of the first heat engine =1400k

T=output temperature of the first heat engine and input temperature of the second heat engine= unknown

T3=output temperature of the second heat engine=300k

but carnot efficiency of heat engine =1 - \frac{Tl}{Th} \\

where Th =temperature at which the heat enters the engine

Tl is the  temperature of the environment

since both engines have the same thermal capacities <em>n_{th} </em> therefore n_{th} =n_{th1} =n_{th2}\\n_{th }=1-\frac{T1}{T}=1-\frac{T}{T3}\\ \\= 1-\frac{1400}{T}=1-\frac{T}{300}\\

We have now that

\frac{-1400}{T}+\frac{T}{300}=0\\

multiplying through by T

-1400 + \frac{T^{2} }{300}=0\\

multiplying through by 300

-420000+ T^{2} =0\\T^2 =420000\\\sqrt{T2}=\sqrt{420000}  \\T=648.07k

The temperature T= 648.07k

5 0
3 years ago
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