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agasfer [191]
3 years ago
15

The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u

pon a rectangular area, 1.5 m by 2.0 m, at right angles. How much total electromagnetic energy falls on the area during 1.0 minute
Physics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

The  total energy is  T  =  169.02 \ J

Explanation:

From the question we are told that

    The  Poynting vector (energy flux ) is  k  =  0.939 \ W/m^2

    The length of the rectangle is  l  =  1.5  \ m

    The  width of the rectangle is  w =  2.0 \ m

    The time taken is t  =   1 \ minute  =  60 \ s

The total electromagnetic energy falls on the area is mathematically represented as

      T  =  k  *  A  *  t

Where A  is the area of the rectangle which is mathematically represented as

           A= l *  w

 substituting values

         A= 2 * 1.5

        A=  3 \ m^2

substituting values

        T  =  0.939 *  3 *  60

        T  =  169.02 \ J

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A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

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As a system expands, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pres
Kaylis [27]

Answer:

Vi = 0.055 m³ = 55 L

Explanation:

From first Law of Thermodynamics, we know that:

ΔQ = ΔU + W

where,

ΔQ = Heat absorbed by the system = 52.5 J

ΔU = Change in Internal Energy = -102.5 J (negative sign shows decrease in internal energy of the system)

W = Work Done in Expansion by the system = ?

Therefore,

52.5 J = - 102.5 J + W

W = 52.5 J + 102.5 J

W = 155 J

Now, the work done in a constant pressure condition is given by:

W = PΔV

W = P(Vf - Vi)

where,

P = Constant Pressure = (0.5 atm)(101325 Pa/1 atm) = 50662.5 Pa

Vf = Final Volume of System = (58 L)(0.001 m³/1 L) = 0.058 m³

Vi = Initial Volume of System = ?

Therefore,

155 J = (50662.5 Pa)(0.058 m³ - Vi)

Vi = 0.058 m³ - 155 J/50662.5 Pa

Vi = 0.058 m³ - 0.003 m³

<u>Vi = 0.055 m³ = 55 L</u>

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PLS HELP. WILL MARK AS THE BRAINLIEST. PLS ANSWER STEP BY STEP.
USPshnik [31]

Answer:12

Explanation:

its the way u read it

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