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agasfer [191]
3 years ago
15

The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u

pon a rectangular area, 1.5 m by 2.0 m, at right angles. How much total electromagnetic energy falls on the area during 1.0 minute
Physics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

The  total energy is  T  =  169.02 \ J

Explanation:

From the question we are told that

    The  Poynting vector (energy flux ) is  k  =  0.939 \ W/m^2

    The length of the rectangle is  l  =  1.5  \ m

    The  width of the rectangle is  w =  2.0 \ m

    The time taken is t  =   1 \ minute  =  60 \ s

The total electromagnetic energy falls on the area is mathematically represented as

      T  =  k  *  A  *  t

Where A  is the area of the rectangle which is mathematically represented as

           A= l *  w

 substituting values

         A= 2 * 1.5

        A=  3 \ m^2

substituting values

        T  =  0.939 *  3 *  60

        T  =  169.02 \ J

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NeX [460]

Answer:

η = 58.8%

Explanation:

Work is defined as the force applied by the distance traveled by the body.

W =F*d

where:

W = work [J] (units of joules)

F = force = 294 [N]

d = distance = 5 [m]

W = 294*5\\W = 1470 [J]\\

Efficiency is defined as the energy required to perform an activity in relation to the energy actually added to perform some activity. This can be better understood by means of the following equation.

efficiency = W_{done}/W_{required}\\efficiency = 1470/2500\\efficiency = 0.588 = 58.8%

5 0
3 years ago
Damping is negligible for a 0.135-kg object hanging from a light, 6.30-N/m spring. A sinusoidal force with an amplitude of 1.70
IceJOKER [234]

Answer:

0.72 Hz minimum frequency

Explanation:

When the damping is negligible,Amplitude is given as

A = (F/m)/[\sqrt{(\omega ^{^{2}}-\omega _{o}^{2}})^2

here \omega _{o}^{2}= k/m = (6.30)/(0.135) = 46.67 N/m kg

F / mA = 1.70/(0.135)(0.480) = 26.2 N/m kg

From the above equation , rearranging for ω,

\omega ^{2}= \omega _{o}^{2}\pm F/m

⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47

⇒ ω = 8.53 or 4.52 rad/s

Frequency = f

ω=2 π f

⇒ f = ω / 2π =  8.53 /6.28  or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz

The lower frequency is 0.72 Hz and higher is 1.36 Hz

8 0
3 years ago
How do I solve the following problem?
lukranit [14]
Use the impulse-momentum theorem.

Ft = mv

Substitute your known values:

(120kg)(20m/s) = F(1.5)

F= 1600N

Hope this helps!
7 0
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What is the momentum of a 2.0kg ball rolling at 6.0 m/s
irga5000 [103]
Momentum can be defined by the formula p=m*V (where m is mass and V is velocity) so if we plug in these numbers:

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4 0
3 years ago
A student has a small metal sphere that hangs from an insulating string. The student, in seeking to determine the charge on the
Leokris [45]

Answer:

the answer the correct one is c

Explanation:

Electric charges of different signs attract and those of the same sign repel. In addition, there are two types of insulating bodies, where the loads are fixed (immobile) and metallic (with mobile loads.

Let's analyze the situation presented

* A rod with positive approaches and the sphere is attracted, so the charge on the sphere is negative

* A rod with a negative charge approaches and the sphere is attracted, therefore the charge of the sphere must be positive.

For this to happen, the sphere must be unloaded and the charge that creates the phenomenon are induced charges because the mobile charges of the same sign as the sphere are repelled.

when checking the answer the correct one is c

8 0
3 years ago
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