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leva [86]
3 years ago
13

If a buffer solution is 0.250 M 0.250 M in a weak base ( K b = 8.0 × 10 − 5 ) Kb=8.0×10−5) and 0.540 M 0.540 M in its conjugate

acid, what is the pH ?
Chemistry
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

9.57

Explanation:

Given that:

pK_{b}=-\log\ K_{b}=-\log(8.0\times 10^{-5})=4.1

Considering the Henderson- Hasselbalch equation for the calculation of the pOH of the basic buffer solution as:

pOH=pK_b+log\frac{[conjugate\ acid]}{[base]}

So,  

pOH=4.1+\log\frac{0.540}{0.250}=4.43

pH + pOH = 14  

So, pH = 14 - 4.43 = 9.57

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Naya [18.7K]

Answer:

The autoionization of water is:

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Explanation

2 moles of water can generate hydronium and hydroxide, when they work as an acid or as a base

If we take account that the concentration of protons (hydroniums), at the standard temperature is 1×10⁻⁷ M, it can be considered that the molarity of water is a constant that can be incorporated into a “greater” constant that also includes to Kc and that is known as ionic product of water, Kw. The expression is:

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