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lbvjy [14]
3 years ago
8

Jeff conducted simple experiment on the effect of rising temperature on food. He concluded that while heat is useful for cooking

food, it can lead to food spoilage if food is left outside in hot weather. He presented his results to his science class. How should the teacher and students respond if they are skeptical? (A) accept Jeff results as true.(B)reject jeffs conclusion.(C)repeat the experiment themselves.(C)be indifferent to jeffs conclusion.(D)ask Jeff to stop experimenting with food.
Chemistry
2 answers:
EleoNora [17]3 years ago
6 0
Repeat the experiment themself
Nina [5.8K]3 years ago
4 0

Answer: Option (C) is the correct answer.

Explanation:

Word "skeptical" means to have doubt. So, when Jeff conducted the experiment then his teacher and other students were skeptical about the results presented by Jeff.

That is, both the teacher and students were not sure whether Jeff's results were correct or not.

Therefore, in order to clear their doubt(s) or verify the results, the teacher and students should repeat the experiment themselves.

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What is the total number of Joules of heat absorbed by 65.0 grams of water when the temperature of the water is raised from 25°C
Norma-Jean [14]

Answer:

Total number of heat absorbed is 4.08kJ

Explanation:

Explanation is contained in the picture attached

5 0
3 years ago
Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because
olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = H_{picric}

So,  H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

The ICE table can be given as:

                          H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

Initial:                0.52                                               0                  0

Change:             - x                                                 + x                 + x

Equilibrium:      0.52 - x                                        + x                 + x

Given that;

acid dissociation constant  (K_a) = 0.42

K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}

0.42 = \frac{[x][x]}{0.52-x}}

0.42 = \frac{[x]^2}{0.52-x}}

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x²  + 0.42x - 0.2184 = 0                   -------------------- (quadratic equation)

Using the quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}    ;     ( where +/-  represent ± )

= \frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}

= \frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}

= \frac{-0.42+\sqrt {1.0496} }{2}     OR   \frac{-0.42-\sqrt {1.0496} }{2}

= \frac{-0.42+1.0245}{2}       OR    \frac{-0.42-1.0245}{2}

= \frac{0.6045}{2}                 OR    -\frac{1.4445}{2}

= 0.30225          OR     - 0.72225

So, we go by the +ve integer that says:

x =  0.30225

x = [ H_3}O^+ ] = [   Picric^- ] =  0.3023  M

∴  the value of  [H3O+] for an 0.52 M solution of picric acid  = 0.3023 M     (to 4 decimal places).

6 0
3 years ago
Which group on the periodic table already stable?
viktelen [127]
The noble gases AKA the column with full outermost valence shells. (Group 18)
7 0
3 years ago
Read 2 more answers
The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p
earnstyle [38]

Answer:

The frequency is  f =  2,01 * 10^{15} \  Hz

Explanation:

From the question we are told that

   The energy required to ionize boron is E_b  =  801 KJ/mol

Generally the ionization energy of boron pre atom is mathematically represented as

     E_a  =  \frac{E_b}{N_A}

Here  N_A is the Avogadro's constant with value N_A  =  6.022*10^{23}

So

      E_a  =  \frac{801}{6.022*10^{23}}

=>     E_a  =  1.330 *10^{-18} \  J/atom

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

       E =  hf  =  E_a

=>     hf  =  E_a

Here h is the Planks constant with value h = 6.626 *10^{-34}

So

       f =  \frac{1.330 *10^{-18}}{ 6.626 *10^{-34}}

=>      f =  2,01 * 10^{15} \  Hz

8 0
3 years ago
What tendency is the standard reduction potential of an element based on?
Y_Kistochka [10]
I think the answer is B :)
3 0
3 years ago
Read 2 more answers
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