The tire pressure is the sum of gauge pressure and the standard pressure of atmospheric pressure
We know that the standard air pressure of surrounding = 101.325 kPa
The given gauge pressure = 413 kPascal
So the tire pressure = 101.325 kPa + 413 = 514.325 K Pa
We can also convert the given pascals to atmosphere or Torr or mmHg or bar
((mass solute)/(mass solution)) * 100% =35%
mass CaCl2=0.35*352.5=123.4 g CaCl2
The question is incomplete, here is the complete question.
A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of copper fluoride in the solution is 
<u>Explanation:</u>
To calculate the molarity of solute, we use the equation:

We are given:
Given mass of copper (II) fluoride = 0.0498 g
Molar mass of copper (II) fluoride = 101.54 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:

Hence, the concentration of copper fluoride in the solution is 
C. the rock may have diferrent textures