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3 years ago

Given 24.3 g of LICI, Find moles of PbCI, produced. PbSO4 + LiCl → PbCl2 + Li2SO4

Chemistry

1 answer:

Tema [17]3 years ago

4 0

Answer:

0.29 moles of PbCl₂

Explanation:

Given data:

Mass of lithium chloride = 24.3 g

Moles of PbCl₂ = ?

Solution:

Chemical equation;

PbSO₄ + 2LiCl → PbCl₂ + Li₂SO₄

Number of moles of LiCl:

Number of moles = mass/ molar mass

Number of moles = 24.3 g/ 42.394 g/mol

Number of moles = 0.57 mol

Now we will compare the moles of PbCl₂ with LiCl .

LiCl : PbCl₂

2 : 1

0.57 : 1/2×0.57 = 0.29 mol

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nikitadnepr [17]

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

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$\rm [B^-]^b$ = anion in an aqueous solution

a, b = relative concentrations of a and b

We have the data given as

$\rm K_{sp}$ for Ag₂CrO₄ is 8 x 10⁻¹²

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Then for a saturated solution, we have

[Ag⁺]=2S

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the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

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To know more about Solubility

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Answer:

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