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Licemer1 [7]
3 years ago
9

How do we usually hear things? Sound waves are made of ___ that pushes together ___.

Physics
1 answer:
denis-greek [22]3 years ago
7 0

A then B, as everything is made of energy and energy pushes the electro magnetic waves into the brain.

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An overhead door is guided by wheels at a and b that roll in horizontal and vertical tracks. when θ = 40°, the velocity of wheel
Karo-lina-s [1.5K]

I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door d)...

The door forms a right triangles that satisfies

\tan\theta=\dfrac ab\implies\sec^2\theta\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac{b\frac{\mathrm da}{\mathrm dt}-a\frac{\mathrm db}{\mathrm dt}}{b^2}

We also have

\tan\theta=\dfrac ab\implies\cos\theta=\dfrac bd

so if you happen to know the height of the door, you can solve for b and a.

d is fixed, so

a^2+b^2=d^2\implies2a\dfrac{\mathrm da}{\mathrm dt}+2b\dfrac{\mathrm db}{\mathrm dt}=0\implies\dfrac{\mathrm da}{\mathrm dt}=-\dfrac ba\dfrac{\mathrm db}{\mathrm dt}

We can solve for the angular velocity \dfrac{\mathrm d\theta}{\mathrm dt}:

\dfrac{\mathrm d\theta}{\mathrm dt}=\cos^2\theta\dfrac{b\left(-\frac ba\frac{\mathrm db}{\mathrm dt}\right)-a\frac{\mathrm db}{\mathrm dt}}{b^2}=-\dfrac1a\dfrac{\mathrm db}{\mathrm dt}

At the point when \theta=40^\circ and \dfrac{\mathrm db}{\mathrm dt}=1.8 ft/s, we get

\dfrac{\mathrm d\theta}{\mathrm dt}=-\dfrac{1.8}a\dfrac{\rm deg}{\rm s}=-\dfrac{1.8}{d\sin40^\circ}\dfrac{\rm deg}{\rm s}

6 0
3 years ago
HURRY PLEASE!!!
REY [17]
90for each walk because 6• 15 = 90
8 0
3 years ago
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An aircraft flying in a straight
Lelechka [254]

Answer:

t = 10.1 s

d = 2020 m

Explanation:

Time to drop from vertical rest

h = ½gt²

t = √(2h/g) = √(2(500)/9.8) = 10.1 s

d = vt = 200(10.1) = 2020 m  

3 0
3 years ago
1. A 180 kg motorcycle travels in a straight line on a horizontal road. The relationship between
Sergio039 [100]
Eh not really sure bout this one
5 0
3 years ago
when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.​
alexira [117]

Answer:

Between the principal focus and the pole of the mirror

4 0
3 years ago
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