I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door
)...
The door forms a right triangles that satisfies

We also have

so if you happen to know the height of the door, you can solve for
and
.
is fixed, so

We can solve for the angular velocity
:

At the point when
and
ft/s, we get

90for each walk because 6• 15 = 90
Answer:
t = 10.1 s
d = 2020 m
Explanation:
Time to drop from vertical rest
h = ½gt²
t = √(2h/g) = √(2(500)/9.8) = 10.1 s
d = vt = 200(10.1) = 2020 m
Eh not really sure bout this one
Answer:
Between the principal focus and the pole of the mirror