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never [62]
3 years ago
5

Every bronsted-lowry acid is also a lewis acid True or False

Chemistry
1 answer:
fenix001 [56]3 years ago
3 0
<h2><em>It is True that every bronsted-lowry acid is also a lewis acid </em></h2>

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Rank the elements from smallest to largest electronegativitu (smallest at top)
Lorico [155]
Ne is the smallest
B is the biggest
It goes (smallest to largest) : Ne, F,C,B
8 0
3 years ago
When 8.0 moles of methanol are reacted with 9.0 moles of oxygen, how many moles of water vapor does the reaction produce?
nadya68 [22]

Answer:

12 moles of H₂O are formed in this combustion.

Explanation:

First of all, think the reaction:

2CH₃OH (l) +  3O₂ (g) →  2CO₂ (g) + 4H₂O (g)

Ratio in the reactants is 2:3, so 2 mol of methanol need 3 mol of oxygen to react. Then 8 mol of CH₃OH, will need (8.3)/2 = 12 moles of O₂

We have 9 moles of O₂, so this is the limiting reactant.

3 mol of oxygen produce 4 mol of water

Then, 9 mol of oxygen will produce ( 9 .4)/3 = 12 moles

3 0
3 years ago
A single covalent bond is made up of​
SIZIF [17.4K]

Answer:

In chemistry, a single bond is a chemical bond between two atoms involving two valence electrons. That is, the atoms share one pair of electrons where the bond forms. Therefore, a single bond is a type of covalent bond.

Explanation:

(copied from Google)

4 0
3 years ago
An amino acid is usually more soluble in aqueous solvent at pH extremes than it is at a pH near the isolelectric point of the am
gogolik [260]

Answer:

Option B. At pH extremes, the amino acid molecules mostly carry a net charge, thus increasing their solubility in polar solvent.

C. At very low or very high pH, the amino acid molecules have increased charge, thus form more salt bonds with water solvent molecules.

Explanation:

4 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
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