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alexdok [17]
3 years ago
10

A runner runs 2.0 km in 5.0 minutes

Physics
2 answers:
nata0808 [166]3 years ago
6 0
But what do we need to do??
Nadya [2.5K]3 years ago
4 0

Answer: What is this supposed to be converted into?

Explanation:

You might be interested in
Describe the motion of an object that has an acceleration of 0m/s2
solong [7]
Zero acceleration means the object's velocity is not changing.
So the object is moving in a straight line, at a constant speed
that could be anything (including zero) as long as it's constant.
6 0
3 years ago
By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect
sergejj [24]

Answer:

Weight\ loss=1.6321N

Explanation:

From the question we are told that:

Weight W=85.9kg

Altitude h= 6.33 km

Let

Radius of Earth r=6380km

Gravity g=9.8m/s^2

Generally the equation for Gravity at altitude is mathematically given by

 g_s=9.8(\frac{6380}{6380+6.33})^2

 g_s=9.781m/s^2

Therefore

Weight at sea level

 W_s=9.8*85.9

 W_s=841.82N

Weight at 6.33 altitude

 W_a=9.781*85.9

 W_a=840.2N

Therefore

 Weight loss=W_s-W_b

 Weight loss=841.82-840.2

 Weight loss=1.6321N

3 0
3 years ago
A 1kg pool ball travels to the right at 2m/s and hits another stopped pool ball bounces back to the left at 1m/s what is the vel
Burka [1]
Ptotal=Ptotal —> m1v1+m2v2=m1v1’+m2v2’ —> (1kg)(2m/s)+(1kg)(0m/s)=(1kg)(-1m/s)+(1kg)(v2’) —> v2’=3m/s

answer: v=3m/s
5 0
3 years ago
Can anyone help me I will give you 30 points
Aleonysh [2.5K]

Answer:

1) ELECTRO MAGNET

2) B

3) -AMOUNT OF ELECTRICITY OF THE POWER SOURCE

- AMOUNT OF COIL WRAPPED UP TO THE NAIK

-CONDUCTIVITY OF THE MEDIUM

3 0
4 years ago
4720 kj of energy are supplied to a material in order to raise its temperature by 65k. if the specific heat capacity of the mate
jeka57 [31]

The mass of material is 26.6 Kg

Given:

Q = 4720 KJ

Change in Temperature (AT) = 65 K

Specific heat capacity of material (c) = 2730 J K Kg*K

The relation between Q, AT, c and m are related by following formula: Q=m* c*∆T,

Plugging value in heat formula:

4720KJ = m* 2730 J/Kg*K * 65K

4720KJ = m * 177450J/kg

Converting 177450 J/kg to Kg/KJ

177450 J/kg*1KJ/1000J = 177.450KJ/kg

Dividing both side by 177.450KJ/kg

4720KJ/177.450KJ/Kg = m*177.450KJ/Kg÷ 177.450KJ/Kg

Hence, the mass of material = 26.6 Kg

Learn more about Mass here:

brainly.com/question/19385703

#SPJ4

6 0
2 years ago
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