Answer:
True
Explanation:
It is true that every element in the periodic table follows the Aufbau's principle.
The principle states that "the sublevels with lower energies are filled up before those with higher energies".
- Sublevels do not fill up in numerical order.
- This is true when writing the electronic configuration of all atoms on the periodic table.
V(H₂O)=500 mL
p(H₂O)=0.9982 g/mL
m(H₂O)=V(H₂O)p(H₂O)
mass of salt solution:
m=m(H₂O)+m(CuSO₄)=V(H₂O)p(H₂O)+m(CuSO₄)
w = m(CuSO₄)/m
w=m(CuSO₄)/{V(H₂O)p(H₂O)+m(CuSO₄)}
w=2.5/{500*0.9982+2.5}=0.004984 (0.4984%)
True
Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.
Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.
A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions. Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.
Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.
Therefore, carbon monoxide CO is a primary pollutant.
Answer:
The equilibrium concentration of 
.
The equilibrium concentration of 
.
The equilibrium concentration of 
.
Explanation:
Answer:
The equilibrium concentration of HCl is 0.01707 M.
Explanation:
Equilibrium constant of the reaction = 
Moles of 
Concentration of ![[PCl_3]=\frac{0.280 mol}{1.00 L}=0.280 M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280%20M)
Moles of 
Concentration of ![[Cl_2]=\frac{0.280 mol}{1.00 L}=0.280M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D%5Cfrac%7B0.280%20mol%7D%7B1.00%20L%7D%3D0.280M)
Initial: 0.280 0.280 0
At eq'm: (0.280-x) (0.280-x) x
We are given:
![[PCl_3]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BPCl_3%5D_%7Beq%7D%3D%280.280-x%29)
![[Cl_2]_{eq}=(0.280-x)](https://tex.z-dn.net/?f=%5BCl_2%5D_%7Beq%7D%3D%280.280-x%29)
![[PCl_5]_{eq}=x](https://tex.z-dn.net/?f=%5BPCl_5%5D_%7Beq%7D%3Dx)
Calculating for 'x'. we get:
The expression of 
for above reaction follows:
![K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BPCl_5%5D%7D%7B%5BPCl_3%5D%5BCl_2%5D%7D)
Putting values in above equation, we get:
On solving this quadratic equation we get:
x = 0.228, 0.344
0.228 M < 0.280 M< 0.344 M
x = 0.228 M
The equilibrium concentration of .
The equilibrium concentration of .
The equilibrium concentration of .
